This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
The question asks to calculate a quantity based on the provided speed-time graph. Assuming the question asks for the total distance covered by the particle, we will calculate the area under the graph. The motion can be divided into three segments: Segment 1 (0 to 10 s): Deceleration from 35 m/s to 20 m/s. This is a trapezium. Segment 2 (10 to 25 s): Constant speed of 20 m/s. This is a rectangle. Segment 3 (25 to 40 s): Deceleration from 20 m/s to 0 m/s (rest). This is a triangle. Step 1: Calculate the distance covered in the first segment (0 to 10 s). The area of a trapezium is given by (1)/(2) × (sum of parallel sides) × height. S_1 = (1)/(2) (35 m/s + 20 m/s) × 10 s S_1 = (1)/(2) (55 m/s) × 10 s S_1 = 55 m/s × 5 s = 275 m Step 2: Calculate the distance covered in the second segment (10 to 25 s). The area of a rectangle is given by length × width. S_2 = 20 m/s × (25 s - 10 s) S_2 = 20 m/s × 15 s = 300 m Step 3: Calculate the distance covered in the third segment (25 to 40 s). The area of a triangle is given by (1)/(2) × base × height. S_3 = (1)/(2) × (40 s - 25 s) × 20 m/s S_3 = (1)/(2) × 15 s × 20 m/s S_3 = 15 s × 10 m/s = 150 m Step 4: Calculate the total distance covered. The total distance is the sum of the distances from each segment. S_total = S_1 + S_2 + S_3 S_total = 275 m + 300 m + 150 m S_total = 725 m The total distance covered by the particle is 725 m. Send me the next one 📸