This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
b) Kelajuan maksimum sebuah kereta lumba F1 ialah 280 km/jam (m/s) Step 1: Write down the given rate. 280 km1 jam Step 2: Convert km to m. (1 km = 1000 m) 280 km1 jam × 1000 m1 km = 280 × 1000 m1 jam = 280000 m1 jam Step 3: Convert jam to saat (s). (1 jam = 60 minit = 3600 saat) 280000 m1 jam × 1 jam3600 s = (280000)/(3600) ms Step 4: Simplify the fraction. (2800)/(36) ms = (700)/(9) ms ≈ 77.78 ms Kelajuan maksimum kereta lumba F1 ialah 77.78 m/s. c) 30 km/liter (m/liter) Step 1: Write down the given rate. 30 km1 liter Step 2: Convert km to m. (1 km = 1000 m) 30 km1 liter × 1000 m1 km = 30 × 1000 m1 liter = 30000 m1 liter Kadar ialah 30000 m/liter.