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Tukar unit berikut kepada m/s dan m/liter: b) Kelajuan maksimum sebuah kereta lumba F1 ialah 280 km/jam c) 30 km/liter

Physics

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2 parts
b

77.78 m/s77.78 \text{ m/s}

c

30000 m/liter30000 \text{ m/liter}

Step-by-step solution

6 steps

Part b· 4 steps

Kelajuan maksimum sebuah kereta lumba F1 ialah 280 km/jam (m/s)

  1. Write down the given rate.

    280 km1 jam\frac{280 \text{ km}}{1 \text{ jam}}
  2. Convert km to m.

    (1 km = 1000 m)

    280 km1 jam×1000 m1 km=280×1000 m1 jam=280000 m1 jam\frac{280 \text{ km}}{1 \text{ jam}} \times \frac{1000 \text{ m}}{1 \text{ km}} = \frac{280 \times 1000 \text{ m}}{1 \text{ jam}} = \frac{280000 \text{ m}}{1 \text{ jam}}
  3. Convert jam to saat (s).

    (1 jam = 60 minit = 3600 saat)

    280000 m1 jam×1 jam3600 s=2800003600ms\frac{280000 \text{ m}}{1 \text{ jam}} \times \frac{1 \text{ jam}}{3600 \text{ s}} = \frac{280000}{3600} \frac{\text{m}}{\text{s}}
  4. Simplify the fraction.

    280036ms=7009ms≈77.78ms\frac{2800}{36} \frac{\text{m}}{\text{s}} = \frac{700}{9} \frac{\text{m}}{\text{s}} \approx 77.78 \frac{\text{m}}{\text{s}}

    Kelajuan maksimum kereta lumba F1 ialah 77.78 m/s\boxed{77.78 \text{ m/s}}.

Part c

30000 m/liter30000 \text{ m/liter}

30 km/liter (m/liter)

  1. Write down the given rate.

    30 km1 liter\frac{30 \text{ km}}{1 \text{ liter}}
  2. Convert km to m.

    (1 km = 1000 m)

    30 km1 liter×1000 m1 km=30×1000 m1 liter=30000 m1 liter\frac{30 \text{ km}}{1 \text{ liter}} \times \frac{1000 \text{ m}}{1 \text{ km}} = \frac{30 \times 1000 \text{ m}}{1 \text{ liter}} = \frac{30000 \text{ m}}{1 \text{ liter}}

    Kadar ialah 30000 m/liter\boxed{30000 \text{ m/liter}}.

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