Two points on a velocity time-graph have coordinates (5 s, 10 ms-1) and (20 s, 20 -1). Calculate the mean acceleration between the two points

April 8, 2026Physics

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Answer

\text{0.667 m/s}^2

4 steps

Let's calculate the mean acceleration.

Identify the given coordinates.
Point 1: $(t_1, v_1) = (5 \text{ s}, 10 \text{ m/s})$
Point 2: $(t_2, v_2) = (20 \text{ s}, 20 \text{ m/s})$
Use the formula for mean acceleration.
Mean acceleration ( $a$ ) is the change in velocity ( $\Delta v$ ) divided by the change in time ( $\Delta t$ ):
$a = \frac{\Delta v}{\Delta t} = \frac{v_2 - v_1}{t_2 - t_1}$
Substitute the values into the formula.
$a = \frac{20 \text{ m/s} - 10 \text{ m/s}}{20 \text{ s} - 5 \text{ s}}$
Calculate the mean acceleration.
$a = \frac{10 \text{ m/s}}{15 \text{ s}}$ $a = \frac{2}{3} \text{ m/s}^2$ $a \approx 0.667 \text{ m/s}^2$
The mean acceleration between the two points is $\text{0.667 m/s}^2$ .