Determine the velocity of an electron with a wavelength of 1 imes 10^-10 m, and calculate the minimum uncertainty in momentum if position uncertainty is 2.0 imes 10^-11 m.

Welcome back preciousinalegwu81@gmail. — been a while! Let's pick up where you left off. First, let's complete the calculation you started for the electron's velocity. Problem: Determine the velocity of an electron with a wavelength of 1 × 10^-10 m, given its mass is 9.11 × 10^-31 kg and Planck's constant (h) is 6.626 × 10^-34 J s. Step 1: Use the de Broglie wavelength formula, = (h)/(mv), and rearrange it to solve for velocity (v). v = (h)/(m) Step 2: Substitute the given values into the formula. v = 6.626 × 10^-34 J s(9.11 × 10^-31 kg) × (1 × 10^-10 m) Step 3: Calculate the velocity. v = 6.626 × 10^-349.11 × 10^-41 m/s v = 0.72733 × 10^7 m/s v = 7.27 × 10^6 m/s Now, let's solve the two numbered questions. 1. Calculate the minimum uncertainty in momentum if position uncertainty is 2.0 × 10^-11 m. Step 1: Use the Heisenberg Uncertainty Principle for minimum uncertainty, which states x p = (h)/(4). Rearrange to solve for the uncertainty in momentum ( p). p = (h)/(4 x) Step 2: Substitute the given values: Planck's constant h = 6.626 × 10^-34 J s and uncertainty in position x = 2.0 × 10^-11 m. p = 6.626 × 10^-34 J s4 × (2.0 × 10^-11 m) Step 3: Calculate the minimum uncertainty in momentum. p = 6.626 × 10^-3425.1327 × 10^-11 kg m/s p = 0.26356 × 10^-23 kg m/s p = 2.64 × 10^-24 kg m/s 2. Determine the momentum of a photon with wavelength 400 nm. Step 1: Use the relationship between momentum (p), Planck's constant (h), and wavelength () for a photon. p = (h)/() Step 2: Convert the wavelength from nanometers (nm) to meters (m) and substitute the values: h = 6.626 × 10^-34 J s and = 400 nm = 400 × 10^-9 m = 4.00 × 10^-7 m. p = 6.626 × 10^-34 J s4.00 × 10^-7 m Step 3: Calculate the momentum of the photon. p = 1.6565 × 10^-27 kg m/s p = 1.66 × 10^-27 kg m/s Send me the next one 📸