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A grey (G) male rabbit was mated with an albino (g) female rabbit. The F1 generation was grey. Show the phenotypic ratio of their offspring if an F1 male was mated with an albino female.

Biology

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here are the solutions for the genetics questions.

2.2 A grey (G) male rabbit was mated with an albino (g) female rabbit. The entire F1 generation was grey. Use a genetic cross to show the phenotypic ratio of their offspring if one of the males of the F1 generation was mated with an albino female.

Step 1: Determine parental genotypes for the first cross.
Since all F1 offspring are grey, grey (G) must be dominant over albino (g). The grey male must be homozygous dominant (GGGG) and the albino female homozygous recessive (gggg).

P:GG×ggP: GG \times gg

Step 2: First cross (P to F1).
Gametes from GGGG: GG
Gametes from gggg: gg

F1:GgF1: Gg

All F1 offspring are heterozygous grey.

Step 3: Second cross (F1 male with albino female).
An F1 male is GgGg. An albino female is gggg.

Gg×ggGg \times gg

Step 4: Perform the Punnett square for the second cross.
Gametes from GgGg: G,gG, g
Gametes from gggg: g,gg, g

GametesGggGggggGggg\begin{array}{|c|c|c|} \hline \text{Gametes} & G & g \\ \hline g & Gg & gg \\ \hline g & Gg & gg \\ \hline \end{array}

Step 5: Determine the genotypic and phenotypic ratios.

  • Genotypes: 50%Gg50\% Gg, 50%gg50\% gg
  • Phenotypes: 50%50\% Grey, 50%50\% Albino
  • Phenotypic ratio: 1 Grey : 1 Albino\boxed{\text{1 Grey : 1 Albino}}

Part 2.2· 4 steps

1 Name the type of Dominance shown.

  • Answer: Complete Dominance\boxed{\text{Complete Dominance}}

2.6 You have two rose plants, both with pink flowers. You cross them and find that, while most of the offspring are pink, some are red and some are white. Use a genetic cross to show how breeding two pink flowering plants can result in pink, red and white flowering plants. Use the letter R for the red allele and W for the white allele.

  1. Identify the type of dominance.

    Since pink flowers result from a cross that also produces red and white flowers, this indicates incomplete dominance where pink is the heterozygous phenotype.

    • Red phenotype: RRRR
    • White phenotype: WWWW
    • Pink phenotype: RWRW
  2. Set up the cross.

    Parents are two pink flowering plants.

    P:RW×RWP: RW \times RW
  3. Perform the Punnett square.

    Gametes from first RWRW: R,WR, W
    Gametes from second RWRW: R,WR, W

    GametesRWRRRRWWRWWW\begin{array}{|c|c|c|} \hline \text{Gametes} & R & W \\ \hline R & RR & RW \\ \hline W & RW & WW \\ \hline \end{array}
  4. Determine the genotypic and phenotypic ratios.

    • Genotypes: 25%RR25\% RR, 50%RW50\% RW, 25%WW25\% WW
    • Phenotypes: 25%25\% Red, 50%50\% Pink, 25%25\% White
    • Phenotypic ratio: 1 Red : 2 Pink : 1 White\boxed{\text{1 Red : 2 Pink : 1 White}}

    3. A blue fly (BB) is crossed with a yellow fly (YY). All of the offspring produced are green (BY).

Part 3.1· 3 steps

Use a genetic cross to show the phenotypic ratio and genotypic ratio off F1 generation.

  1. Set up the cross.

    Parents: Blue fly (BBBB) ×\times Yellow fly (YYYY)

    P:BB×YYP: BB \times YY
  2. Perform the Punnett square.

    Gametes from BBBB: BB
    Gametes from YYYY: YY

    GametesYYBBYBYBBYBY\begin{array}{|c|c|c|} \hline \text{Gametes} & Y & Y \\ \hline B & BY & BY \\ \hline B & BY & BY \\ \hline \end{array}
  3. Determine the genotypic and phenotypic ratios for F1.

    • Genotypes (F1): All BYBY (100%100\%)
    • Phenotypes (F1): All Green (100%100\%)
    • Genotypic ratio: 1 BY\boxed{\text{1 BY}}
    • Phenotypic ratio: 1 Green\boxed{\text{1 Green}}

Part 3.2· 3 steps

Two green flies mate. Illustrate the F2 generation using a genetic cross.

  1. Set up the cross.

    Parents: Green fly (BYBY) ×\times Green fly (BYBY)

    P:BY×BYP: BY \times BY
  2. Perform the Punnett square.

    Gametes from first BYBY: B,YB, Y
    Gametes from second BYBY: B,YB, Y

    GametesBYBBBBYYBYYY\begin{array}{|c|c|c|} \hline \text{Gametes} & B & Y \\ \hline B & BB & BY \\ \hline Y & BY & YY \\ \hline \end{array}
  3. Determine the genotypic and phenotypic ratios for F2.

    • Genotypes (F2): 25%BB25\% BB, 50%BY50\% BY, 25%YY25\% YY
    • Genotypic ratio: 1 BB : 2 BY : 1 YY\boxed{\text{1 BB : 2 BY : 1 YY}}
    • Phenotypes (F2): 25%25\% Blue, 50%50\% Green, 25%25\% Yellow
    • Phenotypic ratio: 1 Blue : 2 Green : 1 Yellow\boxed{\text{1 Blue : 2 Green : 1 Yellow}}

Part 3.3

Name the type of dominance illustrated by this cross.

  • Answer: Codominance\boxed{\text{Codominance}}

4. A male dog that has white fur (WW) is bred with a female dog that has black fur (BB). All the offspring produced have black and white fur.

Part 4.1

Name the type of dominance shown.

  • Answer: Codominance\boxed{\text{Codominance}}

Part 4.2· 3 steps

Use a genetic cross to show the phenotypes and genotypes of the F1 generation.

  1. Set up the cross.

    Parents: White fur male (WWWW) ×\times Black fur female (BBBB)

    P:WW×BBP: WW \times BB
  2. Perform the Punnett square.

    Gametes from WWWW: WW
    Gametes from BBBB: BB

    GametesBBWBWBWWBWBW\begin{array}{|c|c|c|} \hline \text{Gametes} & B & B \\ \hline W & BW & BW \\ \hline W & BW & BW \\ \hline \end{array}
  3. Determine the genotypic and phenotypic ratios for F1.

    • Genotypes (F1): All BWBW (100%100\%)
    • Phenotypes (F1): All Black and white fur (100%100\%)
    • Genotypic ratio: 1 BW\boxed{\text{1 BW}}
    • Phenotypic ratio: 1 Black and white fur\boxed{\text{1 Black and white fur}}
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