Apply the square root property sqrt((a)/(b)) = sqrt(a)sqrt(b).

We know that $\sqrt{81} = 9$.
For $\sqrt{32}$, find the largest perfect square factor of 32. $32 = 16 \times 2$.

$$\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}$$

$$\frac{4\sqrt{2}}{9}$$

The simplified expression is:

$$\boxed{\frac{4\sqrt{2}}{9}}$$

: Evaluate $\sqrt{\frac{32}{128}} - \frac{1}{3}$

$$\frac{1}{2} - \frac{1}{3}$$

To subtract, find a common denominator, which is 6.

$$\frac{1 \times 3}{2 \times 3} - \frac{1 \times 2}{3 \times 2} = \frac{3}{6} - \frac{2}{6}$$

$$\frac{3 - 2}{6} = \frac{1}{6}$$

The result is:

$$\boxed{\frac{1}{6}}$$

: Evaluate $0.13 \times 0.05$

0.13 has 2 decimal places.

0.05 has 2 decimal places.
Total decimal places = $2 + 2 = 4$.

Starting with 65, move the decimal point 4 places to the left, adding leading zeros as needed.

$$0.0065$$

The product is:

$$\boxed{0.0065}$$