Consider albino in Hong Local government where population of the affected individual is 1 in to 100,000, Using Hardy Weinberg formula to calculate 1. Heterozygous 2. Homozygous dominant 3. Recessive allele frequency.

Here's how to solve this genetics problem using the Hardy-Weinberg principle: The Hardy-Weinberg equations are: Allele frequencies: p + q = 1 Genotype frequencies: p^2 + 2pq + q^2 = 1 Where: • p = frequency of the dominant allele • q = frequency of the recessive allele • p^2 = frequency of the homozygous dominant genotype • q^2 = frequency of the homozygous recessive genotype (affected individuals) • 2pq = frequency of the heterozygous genotype (carriers) Given: The frequency of affected individuals (albinos) is 1 in 100,000. Since albinism is a recessive trait, affected individuals have the homozygous recessive genotype. Step 1: Determine the frequency of the homozygous recessive genotype (q^2). q^2 = (1)/(100,000) = 0.00001 Step 2: Calculate the recessive allele frequency (q). q = sqrt(q^2) = sqrt(0.00001) q ≈ 0.003162 Step 3: Calculate the dominant allele frequency (p). Using the allele frequency equation p + q = 1: p = 1 - q = 1 - 0.003162 p ≈ 0.996838 Now, let's calculate the requested values: 3. Recessive allele frequency This is the value of q. q ≈ 0.00316 2. Homozygous dominant allele frequency This refers to the frequency of the homozygous dominant genotype (p^2). p^2 = (0.996838)^2 p^2 ≈ 0.9937 1. Heterozygous allele frequency This refers to the frequency of the heterozygous genotype (2pq). 2pq = 2 × p × q 2pq = 2 × 0.996838 × 0.003162 2pq ≈ 0.00630 That's 2 down. 3 left today — send the next one.