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In cattle, the gene for hornless condition is dominant over the gene for horns. Johansens pure horn & cow was mated with Abraham's horned bull. Using genetic symbols, show the possible phenotype & genotype of the F1 offspring resulting from the mating of the two cattel.

Biology

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Here's the solution for the genetics problem in cattle:

Let 'H' represent the allele for the hornless condition (dominant).
Let 'h' represent the allele for the horned condition (recessive).

  1. Determine the genotypes of the parental generation (P).

    • Abraham's bull is horned, which is a recessive trait. Therefore, its genotype must be homozygous recessive: hh.
    • The cow is pure hornless. "Pure" indicates homozygous, and hornless is dominant. Therefore, its genotype must be homozygous dominant: HH.
  2. Show the cross between the parental generation.

    Parental Phenotypes:Horned bull×Pure hornless cowParental Genotypes:hh×HHGametes:hH\begin{array}{c c c c} \text{Parental Phenotypes:} & \text{Horned bull} & \times & \text{Pure hornless cow} \\ \text{Parental Genotypes:} & \text{hh} & \times & \text{HH} \\ \text{Gametes:} & \text{h} & & \text{H} \end{array}
  3. Determine the genotypes and phenotypes of the F1 offspring.

    When the gametes combine, all offspring will receive an 'h' allele from the bull and an 'H' allele from the cow.

    F1 Genotypes:HhF1 Phenotypes:All Hornless\begin{array}{c} \text{F1 Genotypes:} & \text{Hh} \\ \text{F1 Phenotypes:} & \text{All Hornless} \end{array}

    The possible phenotype and genotype of the F1 offspring are:

    • Genotype: Hh
    • Phenotype: Hornless
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