In cattle, the gene for hornless condition is dominant over the gene for horns. Johansens pure horn & cow was mated with Abraham's horned bull. Using genetic symbols, show the possible phenotype & genotype of the F1 offspring resulting from the mating of the two cattel.

Here's the solution for the genetics problem in cattle: Let 'H' represent the allele for the hornless condition (dominant). Let 'h' represent the allele for the horned condition (recessive). Step 1: Determine the genotypes of the parental generation (P). • Abraham's bull is horned, which is a recessive trait. Therefore, its genotype must be homozygous recessive: hh. • The cow is pure hornless. "Pure" indicates homozygous, and hornless is dominant. Therefore, its genotype must be homozygous dominant: HH. Step 2: Show the cross between the parental generation. c c c c Parental Phenotypes: & Horned bull & × & Pure hornless cow \\ Parental Genotypes: & hh & × & HH \\ Gametes: & h & & H Step 3: Determine the genotypes and phenotypes of the F1 offspring. When the gametes combine, all offspring will receive an 'h' allele from the bull and an 'H' allele from the cow. c F1 Genotypes: & Hh \\ F1 Phenotypes: & All Hornless The possible phenotype and genotype of the F1 offspring are: • Genotype: Hh • Phenotype: Hornless That's 2 down. 3 left today — send the next one.