In pea plants, tallness (T) is dominant over dwarfness (t). Two heterozygous tall plants were crossed. a. State the genotypes of the parents. b. Draw a genetic diagram to show the cross. c. Determine the genotypic ratio of the offspring. d. Determine the phenotypic ratio of the offspring.

Here are the solutions for the pea plant genetics problem. a) State the genotypes of the parents. Step 1: Identify the given information. Tallness (T) is dominant over dwarfness (t). Two heterozygous tall plants were crossed. Step 2: Determine the genotype for heterozygous tall plants. Since tallness (T) is dominant and the plants are heterozygous, they must carry one dominant allele and one recessive allele. The genotype of each parent is Tt. b) Draw a genetic diagram to show the cross. Step 1: Set up the Punnett square for a cross between two heterozygous parents (Tt × Tt). Parents (P): Tt × Tt Gametes: T, t from each parent |c|c|c| Gametes & T & t \\ T & TT & Tt \\ t & Tt & tt \\ c) Determine the genotypic ratio of the offspring. Step 1: Count the genotypes from the Punnett square. TT: 1 Tt: 2 tt: 1 Step 2: Express the genotypes as a ratio. The genotypic ratio is 1 TT : 2 Tt : 1 tt. d) Determine the phenotypic ratio of the offspring. Step 1: Determine the phenotype for each genotype. TT: Tall Tt: Tall (since T is dominant) tt: Dwarf Step 2: Count the phenotypes and express as a ratio. Tall: 1 (TT) + 2 (Tt) = 3 Dwarf: 1 (tt) = 1 The phenotypic ratio is 3 Tall : 1 Dwarf. 3 done, 2 left today. You're making progress.