This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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Experiment I
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2.1 Define the term reaction rate. Reaction rate is the change in concentration of reactants or products per unit time. It measures how quickly reactants are consumed or products are formed.
2.2 Which experiment I or II has a higher reaction rate? Use collision theory to explain the answer.
According to collision theory, for a reaction to occur, reactant particles must collide with sufficient energy (activation energy) and correct orientation. In Experiment I, zinc is in powder form, while in Experiment II, it is in granule form. Powdered zinc has a larger surface area than granular zinc. A larger surface area means more zinc particles are exposed to the hydrochloric acid, leading to a greater frequency of collisions between reactant particles. This results in a higher frequency of effective collisions, thus increasing the reaction rate.
2.3 Write down the factor responsible for the difference in the reaction rates of experiment I and III.
2.4 Explain how the factor named in QUESTION 2.3 affects the reaction rate. A larger surface area of zinc means that more zinc particles are exposed and available to react with the hydrochloric acid particles. This increases the frequency of collisions between the reactant particles. A higher frequency of collisions leads to a higher frequency of effective collisions, which in turn increases the reaction rate.
2.5 Consider experiments II and IV.
2.5.1 How does the value of Q in experiment IV compares to the reaction time (13s) in experiment II. Choose from HIGHER THAN, LOWER THAN or EQUAL TO.
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2.1 Define the term reaction rate. Reaction rate is the change in concentration of reactants or products per unit time.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.