This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Rose, let's knock this out. The original mixture, C, is composed of lead(II) carbonate (PbCO_3) and starch. Here is a simplified explanation of the qualitative analysis: Test 1: Mixing C with distilled water Observation:* The mixture remains a white solid and does not dissolve. Conclusion:* C contains substances that are insoluble in water. Test 2: Adding dilute hydrochloric acid (HCl) or nitric acid (HNO_3) to C Observation:* Fizzing occurs, and a colorless, odorless gas is produced. This gas turns lime water milky. Conclusion:* Carbonate ions (CO_3^2-) are present, as carbon dioxide (CO_2) gas is evolved. Test 3: Heating and cooling the liquid part (filtrate) from the acid test Observation:* A white solid dissolves upon heating and reappears when cooled. Conclusion:* Lead(II) ions (Pb^2+) are present. Test 4: Adding ammonia solution (NH_3(aq)) to the filtrate Observation:* A white solid forms, which does not dissolve even with excess ammonia. Conclusion:* This confirms the presence of lead(II) ions (Pb^2+). Test 5: Adding sodium hydroxide solution (NaOH(aq)) to the filtrate Observation:* A white solid forms initially, then dissolves when excess sodium hydroxide is added. Conclusion:* This also confirms the presence of lead(II) ions (Pb^2+). Test 6: Adding iodine solution to a portion of the original mixture Observation:* The mixture turns blue-black or dark blue. Conclusion:* Starch is present. Send me the next one 📸