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A mixture C contains lead(II) carbonate and starch. Describe the qualitative analysis tests to identify the components.

Chemistry

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Answer

The original mixture, C, is composed of lead(II) carbonate (PbCO3\text{PbCO}_3) and starch.

Here is a simplified explanation of the qualitative analysis:

  • Test 1: Mixing C with distilled water

    • Observation: The mixture remains a white solid and does not dissolve.
    • Conclusion: C contains substances that are insoluble in water.
  • Test 2: Adding dilute hydrochloric acid (HCl) or nitric acid (HNO3\text{HNO}_3) to C

    • Observation: Fizzing occurs, and a colorless, odorless gas is produced. This gas turns lime water milky.
    • Conclusion: Carbonate ions (CO32−\text{CO}_3^{2-}) are present, as carbon dioxide (CO2\text{CO}_2) gas is evolved.
  • Test 3: Heating and cooling the liquid part (filtrate) from the acid test

    • Observation: A white solid dissolves upon heating and reappears when cooled.
    • Conclusion: Lead(II) ions (Pb2+\text{Pb}^{2+}) are present.
  • Test 4: Adding ammonia solution (NH3(aq)\text{NH}_3(\text{aq})) to the filtrate

    • Observation: A white solid forms, which does not dissolve even with excess ammonia.
    • Conclusion: This confirms the presence of lead(II) ions (Pb2+\text{Pb}^{2+}).
  • Test 5: Adding sodium hydroxide solution (NaOH(aq)\text{NaOH}(\text{aq})) to the filtrate

    • Observation: A white solid forms initially, then dissolves when excess sodium hydroxide is added.
    • Conclusion: This also confirms the presence of lead(II) ions (Pb2+\text{Pb}^{2+}).
  • Test 6: Adding iodine solution to a portion of the original mixture

    • Observation: The mixture turns blue-black or dark blue.
    • Conclusion: Starch is present.
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