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A mixture C contains lead(II) carbonate and starch. Describe the qualitative analysis tests to identify the components.
Chemistry
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Answer
The original mixture, C, is composed of lead(II) carbonate () and starch.
Here is a simplified explanation of the qualitative analysis:
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Test 1: Mixing C with distilled water
- Observation: The mixture remains a white solid and does not dissolve.
- Conclusion: C contains substances that are insoluble in water.
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Test 2: Adding dilute hydrochloric acid (HCl) or nitric acid () to C
- Observation: Fizzing occurs, and a colorless, odorless gas is produced. This gas turns lime water milky.
- Conclusion: Carbonate ions () are present, as carbon dioxide () gas is evolved.
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Test 3: Heating and cooling the liquid part (filtrate) from the acid test
- Observation: A white solid dissolves upon heating and reappears when cooled.
- Conclusion: Lead(II) ions () are present.
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Test 4: Adding ammonia solution () to the filtrate
- Observation: A white solid forms, which does not dissolve even with excess ammonia.
- Conclusion: This confirms the presence of lead(II) ions ().
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Test 5: Adding sodium hydroxide solution () to the filtrate
- Observation: A white solid forms initially, then dissolves when excess sodium hydroxide is added.
- Conclusion: This also confirms the presence of lead(II) ions ().
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Test 6: Adding iodine solution to a portion of the original mixture
- Observation: The mixture turns blue-black or dark blue.
- Conclusion: Starch is present.
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