Analyze the provided table for qualitative analysis of mixture C, focusing on the observations and inferences for the tests conducted. What conclusions can be drawn?

Here is a table of possible observations and their corresponding inferences for the qualitative analysis of mixture C, as you would record them during the experiment.

Test	Possible Observation	Inference
(a) Put all of C into a beaker and add about 5 $\text{cm}^3$ of dil. $\text{HNO}_3$. Stir the mixture and filter. Keep the residue and divide the filtrate into two portions.	Effervescence occurs; a colorless, odorless gas is evolved which turns limewater milky.	$\text{CO}_3^{2-}$ (carbonate) is present in the inorganic salt.
	No effervescence.	$\text{CO}_3^{2-}$ (carbonate) is absent.
	A blue solution is formed, and a white residue remains.	A $\text{Cu}^{2+}$ salt is soluble in dilute $\text{HNO}_3$; an insoluble organic compound or inorganic salt is present.
	A colorless solution is formed, and a white residue remains.	A colorless cation salt is soluble in dilute $\text{HNO}_3$; an insoluble organic compound or inorganic salt is present.
(b) (i) To the first portion of the filtrate, add $\text{NaOH(aq)}$ in drops, then in excess.	White precipitate, insoluble in excess $\text{NaOH}$.	$\text{Mg}^{2+}$ or $\text{Ca}^{2+}$ is present.
	White precipitate, soluble in excess $\text{NaOH}$.	$\text{Al}^{3+}$, $\text{Zn}^{2+}$, or $\text{Pb}^{2+}$ is present.
	Blue precipitate, insoluble in excess $\text{NaOH}$.	$\text{Cu}^{2+}$ is present.
	Green precipitate, insoluble in excess $\text{NaOH}$.	$\text{Fe}^{2+}$ is present.
	Reddish-brown precipitate, insoluble in excess $\text{NaOH}$.	$\text{Fe}^{3+}$ is present.
(b) (ii) To the second portion of the filtrate, add $\text{NH}_{3}\text{(aq)}$ in drops, then in excess.	White precipitate, insoluble in excess $\text{NH}_3$.	$\text{Al}^{3+}$ or $\text{Mg}^{2+}$ is present.
	White precipitate, soluble in excess $\text{NH}_3$.	$\text{Zn}^{2+}$ is present.
	Blue precipitate, soluble in excess $\text{NH}_3$ to form a deep blue solution.	$\text{Cu}^{2+}$ is present.
	Green precipitate, insoluble in excess $\text{NH}_3$.	$\text{Fe}^{2+}$ is present.
	Reddish-brown precipitate, insoluble in excess $\text{NH}_3$.	$\text{Fe}^{3+}$ is present.
(c) To the residue, add about 2 $\text{cm}^3$ of distilled water. Boil the mixture and add few drops of iodine solution.	Solution turns blue-black.	Starch is present in the residue (as the organic compound).
	Solution remains yellow/brown (color of iodine).	Starch is absent in the residue.