This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here's the solution to question 3: 3. (a) Concentration of A in g/dm³ Step 1: Calculate the molar mass of H_2SO_4. Molar mass of H_2SO_4 = (2 × 1.0) + 32.0 + (4 × 16.0) = 2.0 + 32.0 + 64.0 = 98.0 g/mol Step 2: Convert the molar concentration of A to g/dm^3. Concentration of A in g/dm^3 = Molarity × Molar mass Concentration of A = 0.100 mol/dm^3 × 98.0 g/mol = 9.80 g/dm^3 The concentration of A in g/dm^3 is 9.80 g/dm^3. 3. (b) Concentration of B in mol/dm³ Step 1: Write the balanced chemical equation for the reaction. Assuming XOH is a monobasic hydroxide, the reaction with sulfuric acid is: H_2SO_4(aq) + 2XOH(aq) X_2SO_4(aq) + 2H_2O(l) From the equation, the mole ratio of H_2SO_4 : XOH is 1:2. So, n_A = 1 and n_B = 2. Step 2: Use the titration formula to find the concentration of B. Given: C_A = 0.100 mol/dm^3 V_A = 12.0 cm^3 = 0.012 dm^3 V_B = 25.0 cm^3 = 0.025 dm^3 (C_A V_A)/(n_A) = (C_B V_B)/(n_B) C_B = (C_A V_A n_B)/(V_B n_A) C_B = 0.100 mol/dm^3 × 0.012 dm^3 × 20.025 dm^3 × 1 C_B = (0.0024)/(0.025) mol/dm^3 C_B = 0.096 mol/dm^3 The concentration of B in mol/dm^3 is 0.096 mol/dm^3. 3. (c) Moles of B in 25.0 cm³ Step 1: Use the concentration of B and the volume to calculate the moles. Moles of B = Concentration of B × Volume of B Moles of B = 0.096 mol/dm^3 × 0.025 dm^3 Moles of B = 0.0024 mol The moles of B in 25.0 cm^3 is 0.0024 mol. 3. (d) Relative atomic mass of X Step 1: Calculate the moles of XOH in 250 cm^3 of solution B. The concentration of B is 0.096 mol/dm^3. Volume of solution B = 250 cm^3 = 0.250 dm^3. Moles of XOH in 250 cm^3 = 0.096 mol/dm^3 ×