This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Hapa kuna suluhisho la tatizo lako: Kwanza, tuandike mlinganyo wa kemikali uliosawazishwa wa mmenyuko wa neutralization: 2NaOH(aq) + H_2SO_4(aq) Na_2SO_4(aq) + 2H_2O(l) Kutoka kwa mlinganyo, uwiano wa moli wa NaOH kwa H₂SO₄ ni 2:1. b) Molarity ya asidi (H₂SO₄) Step 1: Kokotoa moli za hidroksidi ya sodiamu (NaOH). Molarity ya NaOH (M_b) = 0.200 M Volume ya NaOH (V_b) = 25.00 cm^3 = 0.02500 dm^3 Moli za NaOH = M_b × V_b = 0.200 mol/dm^3 × 0.02500 dm^3 = 0.00500 mol Step 2: Tumia uwiano wa moli kukokotoa moli za asidi ya salfa (H₂SO₄). Kutoka kwa mlinganyo, moli 2 za NaOH humenyuka na moli 1 ya H₂SO₄. Moli za H_2SO_4 = Moli za NaOH × (1)/(2) = 0.00500 mol × (1)/(2) = 0.00250 mol Step 3: Kokotoa molarity ya asidi ya salfa (H₂SO₄). Volume ya H₂SO₄ (V_a) = 20.00 cm^3 = 0.02000 dm^3 Molarity ya H_2SO_4 (M_a) = Moli za H_2SO_4V_a = 0.00250 mol0.02000 dm^3 = 0.125 M Molarity ya asidi ni 0.125 M. a) Concentration ya asidi katika gdm⁻³ Step 1: Kokotoa masi ya mola ya H₂SO₄. Masi za atomiki: H = 1.008 g/mol, S = 32.07 g/mol, O = 16.00 g/mol Masi ya mola ya H_2SO_4 = (2 × 1.008) + 32.07 + (4 × 16.00) = 2.016 + 32.07 + 64.00 = 98.086 g/mol Step 2: Badilisha molarity kuwa concentration katika gdm⁻³. Concentration (g/dm^3) = Molarity (mol/dm^3) × Masi ya mola (g/mol) Concentration = 0.125 mol/dm^3 × 98.086 g/mol = 12.26075 g/dm^3 Kuzungusha hadi tarakimu muhimu tatu: Concentration = 12.3 g/dm^3 Concentration ya asidi katika gdm⁻³ ni 12.3 g/dm^3. That's 2 down. 3 left today — send the next one.