This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Another one Mr — let's solve it. Step 1: Write the balanced chemical equation. The reaction between sodium carbonate (Na_2CO_3) and sulphuric acid (H_2SO_4) is: Na_2CO_3 (aq) + H_2SO_4 (aq) → Na_2SO_4 (aq) + H_2O (l) + CO_2 (g) From the balanced equation, the mole ratio of Na_2CO_3 to H_2SO_4 is 1:1. Step 2: Calculate the moles of sodium carbonate. Given: Volume of Na_2CO_3 = 20 cm^3 = 0.020 dm^3 Molarity of Na_2CO_3 = 0.1 M Moles of Na_2CO_3 = Molarity × Volume Moles of Na_2CO_3 = 0.1 mol/dm^3 × 0.020 dm^3 = 0.002 mol Step 3: Determine the moles of sulphuric acid. Since the mole ratio of Na_2CO_3 to H_2SO_4 is 1:1, the moles of H_2SO_4 reacted are equal to the moles of Na_2CO_3. Moles of H_2SO_4 = 0.002 mol Step 4: Calculate the molarity of sulphuric acid. Given: Volume of H_2SO_4 = 13 cm^3 = 0.013 dm^3 Molarity of H_2SO_4 = Moles of H_2SO_4Volume of H_2SO_4 (in dm^3) Molarity of H_2SO_4 = 0.002 mol0.013 dm^3 ≈ 0.1538 M Rounding to three significant figures: Molarity of H_2SO_4 ≈ 0.154 M The molarity of the sulphuric acid used is 0.154 M$. Send me the next one 📸