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In a demonstration to find out the food sample being tested, 1cm3 of dilute sodium hydroxide solution was added to 3cm3 of test solution drop wise. The test tube was shaken thoroughly. A purple colour was observed at the end. Which food substance was being tested and what is the name of the test?

Chemistry

ScanSolve AI Answer

Answer

C

Step-by-step solution

4 steps
  1. Determine the genotypes of the parents.

    Both parents have blood group AB. Blood group AB is a result of codominance between the IAI^A and IBI^B alleles. Therefore, the genotype for blood group AB is IAIBI^A I^B.
    Parent 1 genotype: IAIBI^A I^B
    Parent 2 genotype: IAIBI^A I^B

  2. Set up a Punnett square to determine the possible genotypes of the offspring.

    The gametes produced by each parent will be IAI^A and IBI^B.

    GametesIAIBIAIAIAIAIBIBIAIBIBIB\begin{array}{|c|c|c|} \hline \text{Gametes} & I^A & I^B \\ \hline I^A & I^A I^A & I^A I^B \\ \hline I^B & I^A I^B & I^B I^B \\ \hline \end{array}
  3. Identify the genotypes and corresponding blood groups of the offspring.

    From the Punnett square, the possible genotypes are:

    • IAIAI^A I^A: Blood group A
    • IAIBI^A I^B: Blood group AB
    • IAIBI^A I^B: Blood group AB
    • IBIBI^B I^B: Blood group B
  4. Calculate the percentage of offspring with blood group AB.

    Out of 4 possible offspring combinations, 2 have the genotype IAIBI^A I^B (blood group AB).
    Percentage of offspring with blood group AB = 24×100%=50%\frac{2}{4} \times 100\% = 50\%.

    The correct option is C.

    The final answer is C\boxed{\text{C}}.

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