A) State Gay Lusaac's Law. b) 10cm3 of a gaseous Hydrocarbon, CxHy required 30cm3 of oxygen for complete combustion and 20cm3 of Carbon (IV) Oxide gas were produced, what is the value of x and y?

Ujazo uliotolewa ni:
Ujazo wa CₓHy = $10 \text{ cm}^3$
Ujazo wa O₂ = $30 \text{ cm}^3$
Ujazo wa CO₂ = $20 \text{ cm}^3$

Gawanya ujazo wote kwa ujazo mdogo zaidi ($10 \text{ cm}^3$) ili kupata uwiano wa coefficients:
CₓHy : O₂ : CO₂
$10 \text{ cm}^3 : 30 \text{ cm}^3 : 20 \text{ cm}^3$
$1 : 3 : 2$

Kutoka kwa CO₂:
Coefficient ya CO₂ ni $x$.
Hivyo, $x = 2$.

Coefficient ya O₂ ni $\left(x + \frac{y}{4}\right)$.
Hivyo, $x + \frac{y}{4} = 3$.
Badilisha $x = 2$:
$2 + \frac{y}{4} = 3$
$\frac{y}{4} = 3 - 2$
$\frac{y}{4} = 1$
$y = 4$

Thamani za $x$ na $y$ ni:
$x = \boxed{2}$
$y = \boxed{4}$