This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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c) To identify the two solutions: Step 1: Add dilute hydrochloric acid to a small portion of each unknown solution. • The solution containing sulphite ions will produce a colorless gas with a pungent smell (SO_2), which turns acidified potassium dichromate(VI) solution from orange to green. SO_3^2-(aq) + 2H^+(aq) SO_2(g) + H_2O(l) • The solution containing sulphate ions will show no visible reaction. Step 2: To the solution that showed no reaction with dilute hydrochloric acid (from Step 1), add a few drops of barium chloride solution. • A white precipitate will form, which is insoluble in dilute hydrochloric acid. This confirms the presence of sulphate ions. Ba^2+(aq) + SO_4^2-(aq) BaSO_4(s) 4. a) Isomers are compounds that have the same molecular formula but different structural formulas or different arrangements of atoms in space. 4. b) The molecular formula C_4H_10 has two isomers: • Butane CH_3CH_2CH_2CH_3 • 2-Methylpropane CH_3CH(CH_3)CH_3 4. c) i) • Chlorination of ethane: Free radical substitution • Chlorination of ethene: Electrophilic addition ii) A condition necessary for chlorination of ethane is ultraviolet (UV) light or high temperature. 4. d) Two uses of ethene gas are: • For the ripening of fruits. • In the manufacture of polyethene (a plastic). 4. e) Heat of combustion of a substance is the heat energy released when one mole of a substance undergoes complete combustion in excess oxygen under standard conditions. Send me the next one 📸