This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
To solve this problem, we first need to address the missing titration data. Since no experimental readings are provided for the titration, we will assume a typical average volume of solution A used. Assumption: We will assume the average volume of solution A (H_2SO_4) used in the titration (V_A) is 20.00 cm^3. i) Concentration of B in mol/dm^3 Step 1: Calculate the molar mass of Sodium hydroxide (NaOH). The relative atomic masses are H=1.00, O=16.0, Na=23.0. Molar mass of NaOH = 23.0 + 16.0 + 1.00 = 40.0 g/mol Step 2: Calculate the number of moles of NaOH in 1 g. Moles of NaOH = MassMolar mass = 1.00 g40.0 g/mol = 0.0250 mol Step 3: Calculate the concentration of solution B (NaOH) in mol/dm^3. The volume of solution B is 250 cm^3, which is 0.250 dm^3. Concentration of B (C_B) = Moles of NaOHVolume of solution B = 0.0250 mol0.250 dm^3 = 0.100 mol/dm^3 ii) Concentration of A in mol/dm^3 Step 4: Write the balanced chemical equation and determine the mole ratio. The balanced equation is: H_2SO_4 (aq) + 2NaOH (aq) Na_2SO_4 (aq) + 2H_2O (l) From the equation, 1 mole of H_2SO_4 reacts with 2 moles of NaOH. So, n_A = 1 and n_B = 2. Step 5: Use the titration formula to calculate the concentration of A (H_2SO_4). Given: C_B = 0.100 mol/dm^3 (from part i) V_B = 25 cm^3 = 0.025 dm^3 V_A = 20.00 cm^3 = 0.02000 dm^3 (assumed average volume) The titration formula is: (C_A V_A)/(n_A) = (C_B V_B)/(n_B) Rearranging to solve for C_A: C_A = (C_B V_B n_A)/(V_A n_B) = (0.100 mol/dm^3) × (0.025 dm^3) × 1(0.02000 dm^3) × 2 C_A = (0.0025)/(0.04000) = 0.0625 mol/dm^3 iii) Number of hydrogen ions in 1.0 dm^3 of A Step 6: Calculate the moles of H_2SO_4 in 1.0 dm^3 of solution A. The concentration of A (C_A) is 0.0625 mol/dm^3. Moles of H_2SO_4 = Concentration × Volume = 0.0625 mol/dm^3 × 1.0 dm^3 = 0.0625 mol Step 7: Determine the moles of hydrogen ions (H^+) produced. Sulfuric acid (H_2SO_4) is a strong acid and dissociates completely in water: H_2SO_4 (aq) 2H^+ (aq) + SO_4^2- (aq) Each mole of H_2SO_4 produces 2 moles of H^+ ions. Moles of H^+ ions = 2 × Moles of H_2\