We read your photo as:

Calculate the average volume of H2SO4 used in the titration, given the hypothetical burette readings.

Chemistry

ScanSolve AI Answer

Answer

24.35 cm3\text{24.35 cm}^3

Step-by-step solution

2 steps
  1. State assumptions and tabulate hypothetical results.

    Since no experimental data is provided, we will assume hypothetical burette readings for solution A (H2SO4H_2SO_4) to demonstrate the tabulation and calculation of the average volume. We will also assume a 25 cm³ portion of solution B (XOH) was used for each titration.

    TitrationInitial Burette Reading (cm³)Final Burette Reading (cm³)Volume of A used (cm³)Rough0.0024.5024.5010.0024.3024.3020.0024.4024.40\begin{array}{|c|c|c|c|} \hline \textbf{Titration} & \textbf{Initial Burette Reading (cm³)} & \textbf{Final Burette Reading (cm³)} & \textbf{Volume of A used (cm³)} \\ \hline \text{Rough} & 0.00 & 24.50 & 24.50 \\ \text{1} & 0.00 & 24.30 & 24.30 \\ \text{2} & 0.00 & 24.40 & 24.40 \\ \hline \end{array}
  2. Calculate the average volume of A used.

    Concordant titres are those that are within ±0.10 cm3\pm 0.10 \text{ cm}^3 of each other. From the hypothetical data, the concordant titres are 24.30 cm324.30 \text{ cm}^3 and 24.40 cm324.40 \text{ cm}^3.

    Average volume of A=Sum of concordant volumesNumber of concordant volumes\text{Average volume of A} = \frac{\text{Sum of concordant volumes}}{\text{Number of concordant volumes}} Average volume of A=24.30 cm3+24.40 cm32\text{Average volume of A} = \frac{24.30 \text{ cm}^3 + 24.40 \text{ cm}^3}{2} Average volume of A=48.70 cm32\text{Average volume of A} = \frac{48.70 \text{ cm}^3}{2} Average volume of A=24.35 cm3\text{Average volume of A} = \boxed{\text{24.35 cm}^3}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp