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Balance the following chemical equations: Fe + H2O -> Fe3O4 + H2; Al + O2 -> Al2O3; KClO3 -> KCl + O2; Na + H2O -> NaOH + H2

Chemistry

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Here are the balanced chemical equations for Part B:

  1. Fe+H2O→Fe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2

  1. Balance Fe atoms.

    $$
3\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2
$$

  2. Balance O atoms.

    $$
3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2
$$

  3. Balance H atoms.

    $$
\boxed{3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2}
$$

    2. Al+O2→Al2O3\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3

  4. Balance Al atoms.

    $$
2\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3
$$

  5. Balance O atoms by finding the least common multiple (LCM) of 2 and 3, which is 6.

    $$
4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3
$$

  6. Re-balance Al atoms.

    $$
\boxed{4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3}
$$

    3. KClO3→KCl+O2\text{KClO}_3 \rightarrow \text{KCl} + \text{O}_2

  7. Balance O atoms by finding the LCM of 3 and 2, which is 6.

    $$
2\text{KClO}_3 \rightarrow \text{KCl} + 3\text{O}_2
$$

  8. Balance K and Cl atoms.

    $$
\boxed{2\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2}
$$

    4. Na+H2O→NaOH+H2\text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2

  9. Balance H atoms by making the number of H atoms on the right side even.

    $$
\text{Na} + \text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2
$$

  10. Balance H atoms on the left.

    $$
\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2
$$

  11. Balance Na atoms.

    $$
\boxed{2\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2}
$$

    5. BaCl2+Na2SO4→BaSO4+NaCl\text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + \text{NaCl}

  12. Balance Cl atoms.

    $$
\boxed{\text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaCl}}
$$

    6. Zn+HCl→ZnCl2+H2\text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2

  13. Balance Cl atoms.

    $$
\boxed{\text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2}
$$

    7. Ca(OH)2+CO2→CaCO3+H2O\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}

  14. Check atom count.

    All atoms are already balanced. Ca(OH)2+CO2→CaCO3+H2O \boxed{\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}}

    1. Pb(NO3)2→PbO+NO2+O2\text{Pb(NO}_3)_2 \rightarrow \text{PbO} + \text{NO}_2 + \text{O}_2

  15. Balance N atoms.

    $$
\text{Pb(NO}_3)_2 \rightarrow \text{PbO} + 2\text{NO}_2 + \text{O}_2
$$

  16. To balance O atoms, multiply Pb(NO3)2\text{Pb(NO}_3)_2 by 2.

    $$
2\text{Pb(NO}_3)_2 \rightarrow \text{PbO} + 2\text{NO}_2 + \text{O}_2
$$

  17. Balance Pb atoms.

    $$
2\text{Pb(NO}_3)_2 \rightarrow 2\text{PbO} + 2\text{NO}_2 + \text{O}_2
$$

  18. Re-balance N atoms.

    $$
\boxed{2\text{Pb(NO}_3)_2 \rightarrow 2\text{PbO} + 4\text{NO}_2 + \text{O}_2}
$$
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