Write the balanced chemical equations for the reaction of sulfur(IV) oxide with sodium hydroxide, assuming sulfur(IV) oxide is in excess.

6. When sulfur(IV) oxide (SO₂) is passed into a solution of sodium hydroxide (NaOH) for a long time, it means SO₂ is in excess. Initially, SO₂ reacts with NaOH to form sodium sulfite (Na₂SO₃): SO₂(g) + 2NaOH(aq) → Na₂SO₃(aq) + H₂O(l) If SO₂ continues to be passed, the excess SO₂ reacts with the formed sodium sulfite and water to produce sodium hydrogen sulfite (also known as sodium bisulfite): Na₂SO₃(aq) + H₂O(l) + SO_

Solved: Write the balanced chemical equations for the…

When sulfur(IV) oxide ( $SO_2$ ) is passed into a solution of sodium hydroxide ( $NaOH$ ) for a long time, it means $SO_2$ is in excess. Initially, $SO_2$ reacts with $NaOH$ to form sodium sulfite ( $Na_2SO_3$ ): $SO_2(g) + 2NaOH(aq) \rightarrow Na_2SO_3(aq) + H_2O(l)$ If $SO_2$ continues to be passed, the excess $SO_2$ reacts with the formed sodium sulfite and water to produce sodium hydrogen sulfite (also known as sodium bisulfite):

Write the balanced chemical equations for the reaction of sulfur(IV) oxide with sodium hydroxide, assuming sulfur(IV) oxide is in excess.

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