This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
6. When sulfur(IV) oxide (SO_2) is passed into a solution of sodium hydroxide (NaOH) for a long time, it means SO_2 is in excess. Initially, SO_2 reacts with NaOH to form sodium sulfite (Na_2SO_3): SO_2(g) + 2NaOH(aq) → Na_2SO_3(aq) + H_2O(l) If SO_2 continues to be passed, the excess SO_2 reacts with the formed sodium sulfite and water to produce sodium hydrogen sulfite (also known as sodium bisulfite): Na_2SO_3(aq) + H_2O(l) + SO_