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c) State the chemical family to which element Y belongs.
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2 steps9. c) State the chemical family to which element Y belongs.
Element Y (Potassium) is in Group 1 of the periodic table.
- Chemical family: Alkali metals
9. d) Predict the type of ion formed by element Y and explain why.
Element Y has 1 valence electron. It will lose this electron to achieve a stable electron configuration.
- Type of ion: Cation (specifically, K⁺)
- Explanation: Element Y loses its single valence electron to attain a stable octet electron configuration, similar to a noble gas. Losing an electron results in a positive charge.
9. d) State two reasons why noble gases are chemically stable.
*i) Noble gases have a full outermost electron shell (a stable octet, or duplet for helium).
*ii) This stable electron configuration means they do not readily gain, lose, or share electrons, making them unreactive.
9. e) Give an example of an element under the following category.
*i) Alkaline earth metal: Magnesium (Mg)
*ii) Halogen: Chlorine (Cl)
*iii) Noble gas: Neon (Ne)
10. a) Write the electron arrangement (s and p notation) for the following ions:
i) Na⁺
Neutral sodium (Na) has an atomic number of 11, so its electron configuration is . When it forms Na⁺, it loses one electron from the orbital.
- Electron arrangement:
ii) O²⁻
Neutral oxygen (O) has an atomic number of 8, so its electron configuration is . When it forms O²⁻, it gains two electrons to fill the orbital.
- Electron arrangement:
10. b) Using valency or oxidation numbers, write the chemical formula of:
i) Magnesium chloride
Magnesium (Mg) has a valency of 2 (forms Mg²⁺). Chlorine (Cl) has a valency of 1 (forms Cl⁻). To balance the charges, one Mg²⁺ ion combines with two Cl⁻ ions.
- Chemical formula:
ii) Aluminium oxide
Aluminium (Al) has a valency of 3 (forms Al³⁺). Oxygen (O) has a valency of 2 (forms O²⁻). To balance the charges, two Al³⁺ ions combine with three O²⁻ ions.
- Chemical formula:
10. c) Balance the following chemical equation:
Balance the oxygen atoms.
There are 2 oxygen atoms on the left and 3 on the right. The least common multiple is 6.
Balance the iron atoms.
Now there are iron atoms on the right, and 1 on the left.
The equation is now balanced.
- Balanced equation:
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