This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back Galaxy — missed you this week. Step 1: Understand the relationships for a hydrogen atom. For a hydrogen atom, the velocity of an electron in an orbit is inversely proportional to the principal quantum number n, and the radius of the orbit is directly proportional to the square of the principal quantum number n. v (1)/(n) r n^2 Step 2: Set up the initial and final conditions. Let the initial state be n_1 and the final state be n_2. The electron is initially in the ground state, so n_1 = 1. The initial radius is r_1 = r. The initial velocity is v_1. The final velocity is v_2 = (v_1)/(2). We need to find the final radius r_2. Step 3: Use the velocity relationship to find the new principal quantum number. From v (1)/(n), we have: (v_2)/(v_1) = (n_1)/(n_2) Substitute the given values: (v_1/2)/(v_1) = (1)/(n_2) (1)/(2) = (1)/(n_2) n_2 = 2 So, the electron jumps to the second energy level. Step 4: Use the radius relationship to find the new radius. From r n^2, we have: (r_2)/(r_1) = (n_2^2)/(n_1^2) Substitute the known values: (r_2)/(r) = (2^2)/(1^2) (r_2)/(r) = (4)/(1) r_2 = 4r The new radius will be 4r. The correct option is (b). (b) 4r Send me the next one 📸