This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Write down the balanced chemical equation and the given volumes. The combustion of carbon(II)oxide (CO) in oxygen (O_2) is given by the equation: 2CO_(g) + O_2(g) 2CO_2(g) Initial volume of CO = 50 cm^3 Initial volume of O_2 = 100 cm^3 Step 2: Determine the stoichiometric volume ratio from the balanced equation. According to Gay-Lussac's Law of Gaseous Volumes, the volumes of gaseous reactants and products are in the same ratio as their stoichiometric coefficients in the balanced equation (at constant temperature and pressure). From the equation, 2 volumes of CO react with 1 volume of O_2 to produce 2 volumes of CO_2. The ratio CO : O_2 : CO_2 is 2 : 1 : 2. Step 3: Identify the limiting reactant. Let's determine how much O_2 is needed to react completely with 50 cm^3 of CO: Volume of O_2 needed = 50 cm^3 CO × 1 volume O_22 volumes CO = 25 cm^3 O_2 Since we have 100 cm^3 of O_2 available, and only 25 cm^3 is needed, O_2 is in excess. Therefore, CO is the limiting reactant. Step 4: Calculate the volume of product formed. Since CO is the limiting reactant, the amount of product (CO_2) formed is determined by the initial amount of CO. From the stoichiometric ratio, 2 volumes of CO produce 2 volumes of CO_2. Volume of CO_2 produced = 50 cm^3 CO × 2 volumes CO_22 volumes CO = 50 cm^3 CO_2 Step 5: Calculate the volume of excess reactant remaining. Initial volume of O_2 = 100 cm^3 Volume of O_2 reacted = 25 cm^3 Volume of O_2 remaining = 100 cm^3 - 25 cm^3 = 75 cm^3 Step 6: Calculate the total volume of the resulting mixture. The resulting mixture will consist of the product (CO_2) and the unreacted excess reactant (O_2). Total volume of resulting mixture = Volume of CO_2 produced + Volume of O_2 remaining Total volume = 50 cm^3 + 75 cm^3 = 125 cm^3 The final answer is 125 cm^3.