Write the combustion reaction equation for C2H6!!!

Question

ScanSolve AI Tutor · Accepted Answer

To write the combustion reaction equation for $C_2H_6$ , we react it with oxygen ( $O_2$ ) to produce carbon dioxide ( $CO_2$ ) and water ( $H_2O$ ).

Write the unbalanced equation.
$C_2H_6 + O_2 \rightarrow CO_2 + H_2O$
Balance the carbon atoms.
There are 2 carbon atoms on the left ( $C_2H_6$ ), so we need 2 molecules of $CO_2$ on the right.
$C_2H_6 + O_2 \rightarrow 2CO_2 + H_2O$
Balance the hydrogen atoms.
There are 6 hydrogen atoms on the left ( $C_2H_6$ ), so we need 3 molecules of $H_2O$ on the right ( $3 \times 2 = 6$ ).
$C_2H_6 + O_2 \rightarrow 2CO_2 + 3H_2O$
Balance the oxygen atoms.
Count the oxygen atoms on the right side:
From $2CO_2$ : $2 \times 2 = 4$ oxygen atoms.
From $3H_2O$ : $3 \times 1 = 3$ oxygen atoms.
Total oxygen atoms on the right = $4 + 3 = 7$ .
Since oxygen on the left is in the form of $O_2$ , we need $\frac{7}{2}$ molecules of $O_2$ to get 7 oxygen atoms.
$C_2H_6 + \frac{7}{2}O_2 \rightarrow 2CO_2 + 3H_2O$
Clear the fraction by multiplying the entire equation by 2.
$2(C_2H_6) + 2\left(\frac{7}{2}O_2\right) \rightarrow 2(2CO_2) + 2(3H_2O)$ $2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O$
Verify the balance.
Left side:
Carbon: $2 \times 2 = 4$
Hydrogen: $2 \times 6 = 12$
Oxygen: $7 \times 2 = 14$

Right side:
Carbon: $4 \times 1 = 4$
Hydrogen: $6 \times 2 = 12$
Oxygen: $(4 \times 2) + (6 \times 1) = 8 + 6 = 14$

The equation is balanced.

The final balanced combustion reaction equation for $C_2H_6$ is:

Answer