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Complete the table by giving the values of X, Y, and Z. Elements A and B are involved in bonding. Give the formula of the compound formed.

Chemistry

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Here's the solution to Question 1 (a), (b), (c), and (e) from your exam paper.

Part 1

Part a(i)

X

Complete the table above by giving the values of

Part a(ii)

Y

Part a(iii)· 3 steps

Z

  1. Calculate X (Neutron number for Element A).

    The mass number is the sum of protons and neutrons.

    Mass Number=Proton number+Neutron number\text{Mass Number} = \text{Proton number} + \text{Neutron number} 35=17+X35 = 17 + X X=35−17X = 35 - 17 X=18X = 18

    The value of X is 18\boxed{\text{18}}.

  2. Calculate Y (Electron number for Element A).

    For a neutral atom, the number of electrons is equal to the number of protons.

    Electron number=Proton number\text{Electron number} = \text{Proton number} Y=17Y = 17

    The value of Y is 17\boxed{\text{17}}.

  3. Calculate Z (Mass number for Element C).

    The mass number is the sum of protons and neutrons.

    Mass Number=Proton number+Neutron number\text{Mass Number} = \text{Proton number} + \text{Neutron number} Z=3+4Z = 3 + 4 Z=7Z = 7

    The value of Z is 7\boxed{\text{7}}.

Part b(i)· 2 steps

Give the formula of the compound formed.

Elements A and B are involved in bonding.

  1. Determine the valency of Element A and Element B.

    Element A has 17 protons and 17 electrons (electronic configuration 2, 8, 7). It tends to gain 1 electron to form an ion with a charge of 1−1-.
    Element B has 12 protons and 12 electrons (electronic configuration 2, 8, 2). It tends to lose 2 electrons to form an ion with a charge of 2+2+.

  2. Write the formula of the compound.

    To balance the charges, two A ions (1−1- each) are needed for every one B ion (2+2+).
    The formula of the compound formed is BA2\boxed{\text{BA}_2}.

Part b(ii)

Name the type of bond involved.

Element B (atomic number 12) is a metal, and Element A (atomic number 17) is a non-metal. The bond formed between a metal and a non-metal involves the transfer of electrons.
The type of bond involved is ionic bond\boxed{\text{ionic bond}}.

Part b(iii)· 2 steps

Give the electronic configuration of elements A and D.

  1. Determine the electronic configuration for Element A.

    Element A has an atomic number of 17.
    The electronic configuration is 2, 8, 7\boxed{\text{2, 8, 7}}.

  2. Determine the electronic configuration for Element D.

    Element D has an atomic number of 8.
    The electronic configuration is 2, 6\boxed{\text{2, 6}}.

Part c· 2 steps

To which group of the Periodic Table does elements C and D fall?

  1. Determine the group for Element C.

    Element C has an atomic number of 3 (electronic configuration 2, 1). It has 1 valence electron.
    Element C falls in Group 1\boxed{\text{Group 1}}.

  2. Determine the group for Element D.

    Element D has an atomic number of 8 (electronic configuration 2, 6). It has 6 valence electrons.
    Element D falls in Group 16 (or Group VI)\boxed{\text{Group 16 (or Group VI)}}.

Part e

How would element C be stored in the laboratory?

Element C (atomic number 3) is an alkali metal. Alkali metals are highly reactive with air and water.
Element C would be stored under oil (e.g., paraffin oil or kerosene)\boxed{\text{under oil (e.g., paraffin oil or kerosene)}} to prevent it from reacting with oxygen and moisture in the air.

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