This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here's the solution to question 1 from the exam paper. Question 1: Step 1: Complete the table for atom X and ions Y³⁻ and Z²⁺. Atom X: Mass number = 23 Protons (A) = Electrons = 11 (for a neutral atom) Neutrons (B) = Mass number - Protons = 23 - 11 = 12 Ion Y³⁻: Mass number = 14 Neutrons = 7 Protons (C) = Mass number - Neutrons = 14 - 7 = 7 Electrons (D) = Protons + charge magnitude = 7 + 3 = 10 Ion Z²⁺: Protons = 12 Neutrons = 12 Mass number (E) = Protons + Neutrons = 12 + 12 = 24 Electrons (F) = Protons - charge magnitude = 12 - 2 = 10 The completed values are: A = 11 B = 12 C = 7 D = 10 E = 24 F = 10 Step 2: Identify the cation and anion. A cation* is a positively charged ion. From the table, Z^2+ is a cation. An anion* is a negatively charged ion. From the table, Y^3- is an anion. Cation: Z^2+ Anion: Y^3- Step 3: Write the formula of the compound formed between Z²⁺ and Y³⁻ and identify the bond type. To form a neutral compound, the charges must balance. Z^2+ has a charge of +2. Y^3- has a charge of -3. The least common multiple of 2 and 3 is 6. We need three Z^2+ ions (3 × +2 = +6). We need two Y^3- ions (2 × -3 = -6). The formula of the compound is Z_3Y_2. Since the compound is formed between a metal ion (Z^2+) and a non-metal ion (Y^3-), the bond type is ionic. Formula of the compound: Z_3Y_2 Bond type: Ionic bond What's next?