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Determine the electron arrangement for elements Y and Z given the electron configuration of their ions.

Chemistry

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Answer

2.8.6\text{2.8.6}

2.8.8.2\text{2.8.8.2}

Step-by-step solution

4 steps

10.a)

  1. Determine the number of electrons in the ion Y2−^2-.

    The electron configuration of Y2−^2- is 2.8.8.
    Total electrons in Y2−^2- = 2+8+8=182 + 8 + 8 = 18 electrons.

  2. Determine the number of electrons in the neutral atom Y.

    Since Y2−^2- has gained 2 electrons to become an ion, the neutral atom Y must have had 2 fewer electrons.
    Number of electrons in neutral Y = 18−2=1618 - 2 = 16 electrons.
    The electron arrangement for Y is 2.8.6\boxed{\text{2.8.6}}.

  3. Determine the number of electrons in the ion Z2+^{2+}.

    The electron configuration of Z2+^{2+} is 2.8.8.
    Total electrons in Z2+^{2+} = 2+8+8=182 + 8 + 8 = 18 electrons.

  4. Determine the number of electrons in the neutral atom Z.

    Since Z2+^{2+} has lost 2 electrons to become an ion, the neutral atom Z must have had 2 more electrons.
    Number of electrons in neutral Z = 18+2=2018 + 2 = 20 electrons.
    The electron arrangement for Z is 2.8.8.2\boxed{\text{2.8.8.2}}.

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