This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Hey Gobte, good to see you again. Thank you for providing the full image. Now I have all the necessary data to solve the questions. Question 1: Calculate the concentration of the oxalate solution. Step 1: Determine the mass of sodium oxalate (Na_2C_2O_4) used. From Table 1, the mass of oxalate used is 1.73 g. Step 2: Calculate the number of moles of sodium oxalate. The molar mass of Na_2C_2O_4 is 134.0 g/mol. Moles = MassMolar mass Moles of Na_2C_2O_4 = 1.73 g134.0 g/mol Moles of Na_2C_2O_4 = 0.0129104 mol Step 3: Calculate the concentration of the oxalate solution. From Procedure 1, the sodium oxalate was dissolved in a 250 cm^3 volumetric flask. Volume of solution = 250 cm^3 = 0.250 dm^3. Concentration = MolesVolume (in dm^3) Concentration of Na_2C_2O_4 = 0.0129104 mol0.250 dm^3 Concentration of Na_2C_2O_4 = 0.0516416 mol/dm^3 Rounding to three significant figures: Concentration of oxalate solution = 0.0516 mol/dm^3 Question 2: Calculate the mean titre. Step 1: Identify the accurate burette readings from Table 2. The accurate titres are 26.7 cm^3 and 26.8 cm^3. The approximate titre (28.1 cm^3) is usually discarded for mean calculations. Step 2: Calculate the mean of the accurate titres. Mean titre = 26.7 cm^3 + 26.8 cm^32 Mean titre = 53.5 cm^32 Mean titre = 26.75 cm^3 This matches the value written on the paper. Mean titre = 26.75 cm^3 Question 3: Calculate the concentration of the potassium permanganate solution. Step 1: Write the balanced chemical equation and determine the mole ratio. The reaction between permanganate ions (MnO_4^-) and oxalate ions (C_2O_4^2-), in acidic medium, is: 2MnO_4^-(aq) + 5C_2O_4^2-(aq) + 16H^+(aq) 2Mn^2+(aq) + 10CO_2(g) + 8H_2O(l) From the balanced equation, the mole ratio of KMnO_4 (MnO_4^-) to Na_2C_2O_4 (C_2O_4^2-) is 2:5. So, n_KMnO_4 = 2 and n_Na_2C_2O_4 = 5. Step 2: List the known values. • Concentration of Na_2C_2O_4 (M_Na_2C_2O_4) = 0.0516416 mol/dm^3 (from Question 1) • Volume of Na_2C_2O_4 (V_Na_2C_2O_4) = 25.0 cm^3 (from Procedure 2) • Volume of KMnO_4 (V_KMnO_4) = 26.75 cm^3 (mean titre from Question 2) Step 3: Use the titration formula to calculate the concentration of KMnO_4. The titration formula is: M_KMnO_4 V_KMnO_4n_KMnO_4 = M_Na_2C_2O_4 V_Na_2C_2O_4n_Na_2C_2O_4 Rearranging to solve for M_KMnO_4: M_KMnO_4 = M_Na_2C_2O_4 V_Na_2C_2O_4 n_KMnO_4V_KMnO_4 n_Na_2C_2O_4 Substitute the known values: M_KMnO_4 = (0.0516416 mol/dm^3) × (25.0 cm^3) × 2(26.75 cm^3) × 5 M_KMnO_4 = (2.58208)/(133.75) mol/dm^3 M_KMnO_4 = 0.0193056 mol/dm^3 Rounding to three significant figures: Concentration of KMnO_4 solution = 0.0193 mol/dm^3 What's next?