Calculate the number of moles.1.2,8g of N2 2.5,6 dm to the power three O2 STP

Chemistry

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Here are the calculations for the number of moles:

1. For 2.8 g of N2_{2}

  1. Determine the molar mass of N2_{2}.

    The atomic mass of nitrogen (N) is approximately 14.01 g/mol14.01 \text{ g/mol}.
    Since N2_{2} has two nitrogen atoms, its molar mass is:

    Molar mass of N2=2×14.01 g/mol=28.02 g/mol\text{Molar mass of N}_{2} = 2 \times 14.01 \text{ g/mol} = 28.02 \text{ g/mol}
  2. Calculate the number of moles using the given mass and molar mass.

    Number of moles=MassMolar mass\text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} Number of moles=2.8 g28.02 g/mol\text{Number of moles} = \frac{2.8 \text{ g}}{28.02 \text{ g/mol}} Number of moles≈0.0999 mol\text{Number of moles} \approx 0.0999 \text{ mol} Number of moles≈0.10 mol\text{Number of moles} \approx \boxed{0.10 \text{ mol}}

    2. For 5.6 dm3^{3} of O2_{2} at STP

  3. Recall the molar volume of a gas at Standard Temperature and Pressure (STP).

    At STP, one mole of any ideal gas occupies 22.4 dm322.4 \text{ dm}^{3}.

  4. Calculate the number of moles using the given volume and molar volume at STP.

    Number of moles=VolumeMolar volume at STP\text{Number of moles} = \frac{\text{Volume}}{\text{Molar volume at STP}} Number of moles=5.6 dm322.4 dm3/mol\text{Number of moles} = \frac{5.6 \text{ dm}^{3}}{22.4 \text{ dm}^{3}\text{/mol}} Number of moles=0.25 mol\text{Number of moles} = 0.25 \text{ mol} Number of moles=0.25 mol\text{Number of moles} = \boxed{0.25 \text{ mol}}
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