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A gas mixture contains 20 cm3 of H2, 35 cm3 of O2, 15 cm3 of CO, and 10 cm3 of N2. Calculate the mole fraction of hydrogen in the mixture at S.T.P.

Chemistry

ScanSolve AI Answer

Answer

D

Step-by-step solution

2 steps

To find the mole fraction of hydrogen, we first need to calculate the total volume of the gas mixture. At S.T.P., the number of moles of a gas is directly proportional to its volume, so we can use volumes instead of moles to calculate the mole fraction.

  1. Calculate the total volume of the gas mixture.

    Total volume=Volume of H2+Volume of O2+Volume of CO+Volume of N2\text{Total volume} = \text{Volume of H}_2 + \text{Volume of O}_2 + \text{Volume of CO} + \text{Volume of N}_2 Total volume=20 cm3+35 cm3+15 cm3+10 cm3\text{Total volume} = 20 \text{ cm}^3 + 35 \text{ cm}^3 + 15 \text{ cm}^3 + 10 \text{ cm}^3 Total volume=80 cm3\text{Total volume} = 80 \text{ cm}^3
  2. Calculate the mole fraction of hydrogen.

    Mole fraction of H2=Volume of H2Total volume\text{Mole fraction of H}_2 = \frac{\text{Volume of H}_2}{\text{Total volume}} Mole fraction of H2=20 cm380 cm3\text{Mole fraction of H}_2 = \frac{20 \text{ cm}^3}{80 \text{ cm}^3} Mole fraction of H2=14\text{Mole fraction of H}_2 = \frac{1}{4} Mole fraction of H2=0.25\text{Mole fraction of H}_2 = 0.25

    Comparing this with the given options:
    A. 0.02
    B. 0.16
    C. 0.20
    D. 0.25

    The correct option is D.

    The mole fraction of hydrogen in this mixture is D. 0.25\boxed{\text{D. 0.25}}.

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