This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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To determine the number of water molecules formed in a reaction, we need the balanced chemical equation and the specific quantities (e.g., moles or mass) of the reactants involved. Since these details are not provided, I will assume a typical acid-base neutralization reaction where one mole of water is formed per mole of reaction. Step 1: Consider a general acid-base neutralization reaction. For example, if we consider the reaction between a monoprotic acid and a monobasic alkali, such as: HA(aq) + BOH(aq) BA(aq) + H_2O(l) In this type of reaction, 1 mole of water (H_2O) is formed for every 1 mole of acid and 1 mole of base that react. Step 2: Relate moles of water to the number of molecules. One mole of any substance contains Avogadro's number of particles (molecules, atoms, ions, etc.). Avogadro's number (N_A) is approximately 6.022 × 10^23 mol^-1. Step 3: Calculate the number of water molecules. If 1 mole of water is formed in the reaction, then the number of water molecules formed is equal to Avogadro's number. Number of water molecules = 1 mol × 6.022 × 10^23 molecules/mol Number of water molecules = 6.022 × 10^23 molecules Therefore, if the reaction produces one mole of water, the number of water molecules formed is: 6.022 × 10^23 molecules Last free one today — make it count tomorrow, or type /upgrade for unlimited.