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Draw the structural formula for the following compounds: a) 2-methyl pent-2-ene b) 1-chloro-2-methyl-1-ene c) 1-bromo-3-ethylpentene

Chemistry

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3 parts
a

CH3−C(CH3)=CH−CH2−CH3\text{CH}_3-\text{C}(\text{CH}_3)=\text{CH}-\text{CH}_2-\text{CH}_3

b

Cl−CH=C(CH3)−CH3\text{Cl}-\text{CH}=\text{C}(\text{CH}_3)-\text{CH}_3

c

Br−CH=CH−CH(CH2CH3)−CH2−CH3\text{Br}-\text{CH}=\text{CH}-\text{CH}(\text{CH}_2\text{CH}_3)-\text{CH}_2-\text{CH}_3

Step-by-step solution

9 steps

let's tackle these structural formulas.

3) Draw Structural formula for the following compound

Part a· 3 steps

2-methyl pent-2-ene

  1. Identify the parent chain and the position of the double bond.

    "Pent-2-ene" indicates a 5-carbon chain with a double bond between the second and third carbons.

  2. Identify the substituents and their positions.

    "2-methyl" indicates a methyl group (CH3\text{CH}_3) attached to the second carbon.

  3. Draw the carbon skeleton, add the double bond and substituents, then fill in hydrogen atoms to satisfy carbon's valency of 4.

    CH3−C(CH3)=CH−CH2−CH3\boxed{\text{CH}_3-\text{C}(\text{CH}_3)=\text{CH}-\text{CH}_2-\text{CH}_3}

Part b

Cl−CH=C(CH3)−CH3\text{Cl}-\text{CH}=\text{C}(\text{CH}_3)-\text{CH}_3

1-chloro-2-methyl-1-ene

Assumption: The parent chain is propene (3 carbons) as it's the shortest chain that can accommodate a methyl group at position 2 with a double bond at position 1.

  1. Identify the parent chain and the position of the double bond.

    "Prop-1-ene" indicates a 3-carbon chain with a double bond between the first and second carbons.

  2. Identify the substituents and their positions.

    "1-chloro" indicates a chlorine atom on the first carbon. "2-methyl" indicates a methyl group (CH3\text{CH}_3) on the second carbon.

  3. Draw the carbon skeleton, add the double bond and substituents, then fill in hydrogen atoms.

    Cl−CH=C(CH3)−CH3\boxed{\text{Cl}-\text{CH}=\text{C}(\text{CH}_3)-\text{CH}_3}

Part c

Br−CH=CH−CH(CH2CH3)−CH2−CH3\text{Br}-\text{CH}=\text{CH}-\text{CH}(\text{CH}_2\text{CH}_3)-\text{CH}_2-\text{CH}_3

1-bromo-3-ethylpentene

Assumption: The double bond is at position 1, making it pent-1-ene, as the position is not specified.

  1. Identify the parent chain and the position of the double bond.

    "Pent-1-ene" indicates a 5-carbon chain with a double bond between the first and second carbons.

  2. Identify the substituents and their positions.

    "1-bromo" indicates a bromine atom on the first carbon. "3-ethyl" indicates an ethyl group (CH2CH3\text{CH}_2\text{CH}_3) on the third carbon.

  3. Draw the carbon skeleton, add the double bond and substituents, then fill in hydrogen atoms.

    Br−CH=CH−CH(CH2CH3)−CH2−CH3\boxed{\text{Br}-\text{CH}=\text{CH}-\text{CH}(\text{CH}_2\text{CH}_3)-\text{CH}_2-\text{CH}_3}
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