Give the equation with NaI

Here is the overall equation for the reaction of concentrated sulfuric acid with sodium iodide:

Step 1: Write the overall balanced chemical equation.
Sodium iodide reacts with concentrated sulfuric acid, where the iodide ions reduce the sulfuric acid.

$$\boxed{2\text{NaI(s)} + 3\text{H}_2\text{SO}_4\text{(conc)} \longrightarrow 2\text{NaHSO}_4\text{(s)} + \text{I}_2\text{(s)} + \text{SO}_2\text{(g)} + 2\text{H}_2\text{O(l)}}$$