This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the solutions to the questions: 1. i) Hydroxonium ion: H_3O^+ ii) Ammonium ion: NH_4^+ 4. Step 1: Calculate the moles of hydrogen peroxide (H_2O_2). Moles of H_2O_2 = Concentration × Volume Moles of H_2O_2 = 0.02 mol dm^-3 × 200 dm^3 = 4 mol Step 2: Use the mole ratio from the balanced ionic equation to find the moles of manganate(VII) ions (MnO_4^-). The equation is: 2MnO_4^-(aq) + 6H^+(aq) + 5H_2O_2(aq) 2Mn^2+(aq) + 8H_2O(l) + 5O_2(g) From the equation, 5 moles of H_2O_2 react with 2 moles of MnO_4^-. Moles of MnO_4^- = (2)/(5) × Moles of H_2O_2 Moles of MnO_4^- = (2)/(5) × 4 mol = 1.6 mol Step 3: Calculate the volume of acidified potassium manganate(VII). Volume of KMnO_4 = Moles of MnO_4^-Concentration of KMnO_4 Volume of KMnO_4 = 1.6 mol0.02 mol dm^-3 = 80 dm^3 The volume of acidified potassium manganate(VII) is 80 dm^3. 5. Step 1: Calculate the moles of magnesium (Mg). Moles of Mg = Mass of MgMolar mass of Mg Moles of Mg = 3.6 g24 g/mol = 0.15 mol Step 2: Calculate the mass of chlorine (Cl) in the chloride formed. Mass of Cl = Mass of chloride formed - Mass