Identify the reactant and reaction conditions.

The reactant is phenyl benzoate, which consists of two benzene rings connected by an ester linkage. The reaction conditions are $\text{HNO}_3/\text{H}_2\text{SO}_4$, which indicates nitration, an electrophilic aromatic substitution reaction.

Phenyl benzoate has the structure $\text{C}_6\text{H}_5\text{COOC}_6\text{H}_5$.
Let's label the two benzene rings:

• Ring 1 (Benzoyl part): This ring is directly attached to the carbonyl carbon ($\text{C=O}$). The -COOR group is an electron-withdrawing group by resonance and induction. It deactivates the benzene ring towards electrophilic substitution and is a meta-director.
• Ring 2 (Phenolic part): This ring is directly attached to the oxygen atom of the ester linkage. The -OR group (where R is the acyl group) is an electron-donating group by resonance (due to the lone pairs on oxygen). It activates the benzene ring towards electrophilic substitution and is an ortho-para director.

Electrophilic aromatic substitution reactions preferentially occur on the more activated benzene ring. Since Ring 2 (phenolic part) is activated and Ring 1 (benzoyl part) is deactivated, the nitration will occur on Ring 2.

The -OR group is an ortho-para director. Between the ortho and para positions, the para position is generally the major product due to less steric hindrance.

Based on the analysis, the nitro group ($\text{NO}_2$) should be introduced at the para position of the phenolic ring (the ring attached to the oxygen atom).

• (a) Shows nitration on the meta position of the benzoyl ring (incorrect).
• (b) Shows nitration on the para position of the benzoyl ring (incorrect).
• (c) Shows nitration on the para position of the phenolic ring (correct).
• (d) Shows nitration on the meta position of the phenolic ring (incorrect).

Therefore, option (c) represents the major product.

The final answer is $\boxed{\text{c}}$