The given reaction is:
2X+4Y→3Z+Q
The given data for reactant Y is:
- Initial time (t1) = 0.00 s
- Final time (t2) = 11.0 s
- Initial concentration of Y ([Y]1) = 1.358 M
- Final concentration of Y ([Y]2) = 0.407 M
Step 1: Calculate the change in concentration of Y (Δ[Y]) and the change in time (Δt).
Δ[Y]=[Y]2−[Y]1=0.407M−1.358M=−0.951M
Δt=t2−t1=11.0s−0.00s=11.0s
Step 2: Calculate the rate of disappearance of Y.
The rate of disappearance of Y is given by −ΔtΔ[Y].
RateofdisappearanceofY=−11.0s−0.951M=11.0s0.951M
RateofdisappearanceofY≈0.08645M/s
a) The rate of disappearance of Y is 0.0865M/s
Step 3: Calculate the rate of disappearance of X.
From the stoichiometry of the reaction (2X and 4Y), the relationship between their rates is:
−21ΔtΔ[X]=−41ΔtΔ[Y]
RateofdisappearanceofX=−ΔtΔ[X]=42(−ΔtΔ[Y])=21×(RateofdisappearanceofY)
RateofdisappearanceofX=21×0.08645M/s≈0.043225M/s
b) The rate of disappearance of X is 0.0432M/s
Step 4: Calculate the rate of appearance of Z.
From the stoichiometry of the reaction (4Y and 3Z), the relationship between their rates is:
31ΔtΔ[Z]=−41ΔtΔ[Y]
RateofappearanceofZ=ΔtΔ[Z]=43(−ΔtΔ[Y])=43×(RateofdisappearanceofY)
RateofappearanceofZ=43×0.08645M/s≈0.0648375M/s
c) The rate of appearance of Z is 0.0648M/s
Step 5: Calculate the rate of appearance of Q.
From the stoichiometry of the reaction (4Y and 1Q), the relationship between their rates is:
11ΔtΔ[Q]=−41ΔtΔ[Y]
RateofappearanceofQ=ΔtΔ[Q]=41(−ΔtΔ[Y])=41×(RateofdisappearanceofY)
RateofappearanceofQ=41×0.08645M/s≈0.0216125M/s
d) The rate of appearance of Q is 0.0216M/s
Step 6: Calculate the overall rate of reaction.
The overall rate of reaction is defined as:
OverallRate=−21ΔtΔ[X]=−41ΔtΔ[Y]=31ΔtΔ[Z]=11ΔtΔ[Q]
Using the rate of disappearance of Y:
OverallRate=−41ΔtΔ[Y]=41×(RateofdisappearanceofY)
OverallRate=41×0.08645M/s≈0.0216125M/s
e) The overall rate of reaction is 0.0216M/s
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