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In the given reaction:

Chemistry

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Answer

D

Step-by-step solution

3 steps

In the given reaction:

SbF5+BrF3↔BrF2++SbF6−\text{SbF}_5 + \text{BrF}_3 \leftrightarrow \text{BrF}_2^+ + \text{SbF}_6^-
  1. Analyze the transfer of species.

    In this reaction, BrF₃ donates a fluoride ion (F⁻) to form BrF₂⁺.

    BrF3→BrF2++F−\text{BrF}_3 \rightarrow \text{BrF}_2^+ + \text{F}^-

    SbF₅ accepts this fluoride ion (F⁻) to form SbF₆⁻.

    SbF5+F−→SbF6−\text{SbF}_5 + \text{F}^- \rightarrow \text{SbF}_6^-
  2. Determine the role of SbF₅.

    According to the Lewis acid-base theory, a Lewis acid is a species that accepts an electron pair. In the context of fluoride ion transfer, a species that accepts a fluoride ion (which carries an electron pair) acts as a Lewis acid. Since SbF₅ accepts a fluoride ion, it is acting as a Lewis acid.

  3. Compare with the given options.

    A: buffer - A buffer resists changes in pH. This is not the primary role here.
    B: indicator - An indicator signals the presence of a substance or a change in conditions. This is not the role here.
    C: base - A base is an electron pair donor or a proton acceptor. SbF₅ is an acceptor, not a donor.
    D: acid - An acid is an electron pair acceptor or a proton donor. SbF₅ acts as an electron pair acceptor (specifically, a fluoride ion acceptor), which classifies it as an acid (Lewis acid).

    The correct option is D.

    The final answer is D:acid\boxed{\text{D:acid}}.

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