This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Fresh day Born, let's solve. Step 1: Balance the chemical equation. The given unbalanced equation is: CaCO_3 + HCl → CaCl_2 + H_2O + CO_2 To balance the chlorine atoms, we need 2 molecules of HCl. This also balances the hydrogen atoms. The balanced equation is: CaCO_3 + 2HCl → CaCl_2 + H_2O + CO_2 Step 2: Calculate the molar mass of CaCO_3. Atomic masses: Ca = 40.08 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. Molar mass of CaCO_3 = 40.08 + 12.01 + (3 × 16.00) = 40.08 + 12.01 + 48.00 = 100.09 g/mol. Step 3: Calculate the number of moles of CaCO_3. Given mass of CaCO_3 = 25 g. Moles of CaCO_3 = MassMolar mass = 25 g100.09 g/mol ≈ 0.2498 mol Step 4: Use the mole ratio from the balanced equation to find the moles of CaCl_2. From the balanced equation, 1 mole of CaCO_3 produces 1 mole of CaCl_2. Therefore, the number of moles of CaCl_2 obtained is equal to the number of moles of CaCO_3. Moles of CaCl_2 = Moles of CaCO_3 = 0.2498 mol The number of moles of CaCl_2 that can be obtained is approximately 0.250 mol. Got more? Send 'em.