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Describe the industrial extraction of copper metal from its major ore, chalcopyrite.

Chemistry

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a

CuFeS2\text{CuFeS}_2

a) The formula of the major ore of copper metal is chalcopyrite.

CuFeS2\boxed{\text{CuFeS}_2}

b) Process (II) is froth flotation.

c) The reaction that occurs in stage (III) is the roasting of chalcopyrite in air to produce copper(I) sulfide and iron(II) oxide.

2CuFeS2(s)+4O2(g)→Cu2S(s)+2FeO(s)+3SO2(g)2\text{CuFeS}_2(s) + 4\text{O}_2(g) \rightarrow \text{Cu}_2\text{S}(s) + 2\text{FeO}(s) + 3\text{SO}_2(g)

d) In stage (IV), copper(I) sulfide is heated in a converter with air and sand (SiO2\text{SiO}_2). Iron impurities are oxidized to FeO\text{FeO}, which reacts with SiO2\text{SiO}_2 to form FeSiO3\text{FeSiO}_3 slag. The Cu2S\text{Cu}_2\text{S} then undergoes self-reduction: some is oxidized to Cu2O\text{Cu}_2\text{O}, which reacts with remaining Cu2S\text{Cu}_2\text{S} to produce molten copper and SO2\text{SO}_2 gas. This molten copper is blister copper.

e) The half-cell equations for the reactions occurring at the anode and cathode in stage (VII) (electrolytic refining) are:

At the anode (oxidation):

Cu(s)→Cu2+(aq)+2e−\text{Cu}(s) \rightarrow \text{Cu}^{2+}(aq) + 2e^-

At the cathode (reduction):

Cu2+(aq)+2e−→Cu(s)\text{Cu}^{2+}(aq) + 2e^- \rightarrow \text{Cu}(s)
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