This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're on a roll — here are the solutions to the exercises: EXERCISE 1. Write the IUPAC name of the following compounds: a)* (CH₃)₂CHCH=CHCH₂CH₃ Step 1: Expand the condensed formula: CH₃-CH(CH₃)-CH=CH-CH₂-CH₃. Step 2: Identify the longest carbon chain containing the double bond. This chain is 6 carbons long (hexene). Step 3: Number the chain to give the double bond the lowest possible number. Numbering from the left places the double bond at C3 and the methyl group at C2. Numbering from the right places the double bond at C3 and the methyl group at C5. Prioritize the lowest substituent number when the multiple bond position is the same. Name: 2-methylhex-3-ene* b)* CH-CH=CH-CH_2-CH_3 Step 1: Identify the longest carbon chain containing both multiple bonds. This chain is 6 carbons long (hex). Step 2: Number the chain to give the multiple bonds the lowest possible locants. Numbering from the left: triple bond at C1, double bond at C3. Locants: (1, 3). Numbering from the right: double bond at C3, triple bond at C5. Locants: (3, 5). The set (1, 3) is lower than (3, 5), so number from the left. Step 3: Name the compound, dropping the 'e' from 'ene' before 'yne'. Name: hex-3-en-1-yne* 2. Write the structural formula of the following: a)* 3-propylpenta-1,3-diene Step 1: The parent chain is penta-1,3-diene, meaning 5 carbons with double bonds at C1 and C3. Step 2: Add a propyl group at C3. CH_2=CH-C(CH_2CH_2CH_3)=CH-CH_3 b)* oct-2-ene-5-yne Step 1: The parent chain is oct, meaning 8 carbons. Step 2: Add a double bond at C2 and a triple bond at C5. CH_3-CH=CH-CH_2-C-CH_2-CH_3 c)* hex-1,3-diene-5-yne Step 1: The parent chain is hex, meaning 6 carbons. Step 2: Add double bonds at C1 and C3, and a triple bond at C5. CH_2=CH-CH=CH-C d)* 3-ethylpenta-2-chloro-1,4-diene Step 1: The parent chain is penta-1,4-diene, meaning 5 carbons with double bonds at C1 and C4. Step 2: Add a chloro group at C2 and an ethyl group at C3. CH_2=CCl-CH(CH_2CH_3)-CH=CH_2 e)* 2,3-dimethylbut-1-ene Step 1: The parent chain is but-1-ene, meaning 4 carbons with a double bond at C1. Step 2: Add methyl groups at C2 and C3. CH_2=C(CH_3)-CH(CH_3)-CH_3 Got more? Send 'em!