What are the IUPAC names for the following organic compounds?

Here are the names for the 11 compounds:

1. CH₃—CH₂—CH₂—OH

   • Longest chain with -OH: 3 carbons. -OH on C1.
   • Name: $\boxed{\text{Propan-1-ol}}$

2. HO—CH₂—CH₂—OH

   • Longest chain with -OH groups: 2 carbons. -OH groups on C1 and C2.
   • Name: $\boxed{\text{Ethane-1,2-diol}}$

3. HO—CH₂—CH(OH)—CH₂—OH

   • Longest chain with -OH groups: 3 carbons. -OH groups on C1, C2, and C3.
   • Name: $\boxed{\text{Propane-1,2,3-triol}}$

4. CH₃—CH(OH)—CH₃

   • Longest chain with -OH: 3 carbons. -OH on C2.
   • Name: $\boxed{\text{Propan-2-ol}}$

5. CH₃—CH(OH)—CH₂—CH₃

   • Longest chain with -OH: 4 carbons. Numbering from the right gives -OH on C2.
   • Name: $\boxed{\text{Butan-2-ol}}$

6. CH₃—CH(OH)—CH(CH₃)—CH₂—CH₃

   • Longest chain with -OH: 5 carbons (pentane). Numbering from the left gives -OH on C2 and -CH₃ on C3.
   • Name: $\boxed{\text{3-methylpentan-2-ol}}$

7. CH₃—CH(CH₃)—CH₂—CH₂—CH(OH)—CH₃

   • Longest chain with -OH: 6 carbons (hexane). Numbering from the right gives -OH on C2 and -CH₃ on C5.
   • Name: $\boxed{\text{5-methylhexan-2-ol}}$

8. Cyclopentane with an -OH group

   • Cyclic alcohol with 5 carbons.
   • Name: $\boxed{\text{Cyclopentanol}}$

9. Cyclopentane ring with -OH, -Br, and -Cl

   • Number the ring starting with -OH as C1. Then number to give substituents the lowest possible numbers. Clockwise numbering gives -Br on C2 and -Cl on C3.
   • Name: $\boxed{\text{2-bromo-3-chlorocyclopentanol}}$

10. CH₃—C(CH₃)(OH)—C(Br)(Br)—CH₃

    • Longest chain with -OH: 4 carbons (butane). Numbering from the left gives -OH on C2.
    • Substituents: methyl on C2, two bromo groups on C3.
    • Name: $\boxed{\text{3,3-dibromo-2-methylbutan-2-ol}}$

11. CH₃—CH₂—CH(CH₂Cl)—CH(CH₃)—CH₂OH

    • Longest carbon chain containing the -OH group: 5 carbons (pentane). Numbering from the right gives -OH on C1.
    • Substituents: methyl on C2, chloromethyl on C3.
    • Name: $\boxed{\text{3-(chloromethyl)-2-methylpentan-1-ol}}$