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List three natural carbonates and give examples of soluble and insoluble ones. Write the reaction equation for CO2 gas and baryta water over 5 mins.

Chemistry

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here are the answers to your tutorial questions:

1. a) List three natural carbonates you have studied.

  • Calcium carbonate (CaCO3\text{CaCO}_3) - found as limestone, marble, chalk.
  • Magnesium carbonate (MgCO3\text{MgCO}_3) - found as magnesite.
  • Iron(II) carbonate (FeCO3\text{FeCO}_3) - found as siderite.

Part b

Give three examples of carbonates that are soluble in water and three that are not.

  • Soluble carbonates:
    • Sodium carbonate (Na2CO3\text{Na}_2\text{CO}_3)
    • Potassium carbonate (K2CO3\text{K}_2\text{CO}_3)
    • Ammonium carbonate ((NH4)2CO3\text{(NH}_4)_2\text{CO}_3)
  • Insoluble carbonates:
    • Calcium carbonate (CaCO3\text{CaCO}_3)
    • Magnesium carbonate (MgCO3\text{MgCO}_3)
    • Copper(II) carbonate (CuCO3\text{CuCO}_3)

Part c· 2 steps

Write the equation for the reaction between CO2\text{CO}_2 gas and baryta water taken place for over 5mins.

  1. Carbon dioxide reacts with barium hydroxide (baryta water) to form a white precipitate of barium carbonate.

    Ba(OH)2(aq)+CO2(g)→BaCO3(s)+H2O(l)\text{Ba(OH)}_2(\text{aq}) + \text{CO}_2(\text{g}) \rightarrow \text{BaCO}_3(\text{s}) + \text{H}_2\text{O}(\text{l})
  2. If excess carbon dioxide is passed for an extended period (over 5 minutes), the insoluble barium carbonate reacts further with carbon dioxide and water to form soluble barium hydrogen carbonate, causing the precipitate to redissolve.

    BaCO3(s)+CO2(g)+H2O(l)→Ba(HCO3)2(aq)\text{BaCO}_3(\text{s}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\text{l}) \rightarrow \text{Ba(HCO}_3)_2(\text{aq})

    2. Distinguish between Na2CO3\text{Na}_2\text{CO}_3 and KHCO3\text{KHCO}_3 using the available reagents.

    Here are three simple tests:

    • Test 1: Using Phenolphthalein indicator

      • Procedure: Add a few drops of phenolphthalein indicator to separate solutions of Na2CO3\text{Na}_2\text{CO}_3 and KHCO3\text{KHCO}_3.
      • Observation: The Na2CO3\text{Na}_2\text{CO}_3 solution will turn pink/red (strongly alkaline), while the KHCO3\text{KHCO}_3 solution will show a faint pink color or remain colorless (less alkaline).
      • Explanation: Sodium carbonate is a salt of a strong base and a weak acid, leading to significant hydrolysis and a higher pH. Potassium hydrogen carbonate is less alkaline.
    • Test 2: Using Magnesium Sulfate (MgSO4\text{MgSO}_4) solution

      • Procedure: Add magnesium sulfate solution to separate solutions of Na2CO3\text{Na}_2\text{CO}_3 and KHCO3\text{KHCO}_3 at room temperature.
      • Observation: With Na2CO3\text{Na}_2\text{CO}_3, an immediate white precipitate of magnesium carbonate forms. With KHCO3\text{KHCO}_3, no precipitate forms in the cold solution. A precipitate would only form upon heating the KHCO3\text{KHCO}_3 mixture.
      • Equations: Na2CO3(aq)+MgSO4(aq)→MgCO3(s)+Na2SO4(aq)\text{Na}_2\text{CO}_3(\text{aq}) + \text{MgSO}_4(\text{aq}) \rightarrow \text{MgCO}_3(\text{s}) + \text{Na}_2\text{SO}_4(\text{aq}) 2KHCO3(aq)+MgSO4(aq)→Mg(HCO3)2(aq)+K2SO4(aq)2\text{KHCO}_3(\text{aq}) + \text{MgSO}_4(\text{aq}) \rightarrow \text{Mg(HCO}_3)_2(\text{aq}) + \text{K}_2\text{SO}_4(\text{aq}) (Magnesium bicarbonate is soluble)
    • Test 3: Using Barium Chloride (BaCl2\text{BaCl}_2) solution

      • Procedure: Add barium chloride solution to separate solutions of $\text{Na
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