This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here are the solutions to the problems: Question 7: How many grams of hydrogen are in 24.0 grams of C₆H₆? Step 1: Determine the molar mass of C₆H₆. Atomic mass of Carbon (C) ≈ 12.01 g/mol Atomic mass of Hydrogen (H) ≈ 1.008 g/mol Molar mass of C₆H₆ = (6 × 12.01 g/mol) + (6 × 1.008 g/mol) = 72.06 g/mol + 6.048 g/mol = 78.108 g/mol Step 2: Calculate the mass of hydrogen in one mole of C₆H₆. Mass of H in C₆H₆ = 6 × 1.008 g/mol = 6.048 g/mol Step 3: Calculate the grams of hydrogen in 24.0 grams of C₆H₆. We use the ratio of the mass of hydrogen to the molar mass of C₆H₆. Grams of H = ( Mass of H in C₆H₆Molar mass of C₆H₆ ) × Total mass of C₆H₆ = ( 6.048 g78.108 g ) × 24.0 g = 0.07743 × 24.0 g = 1.85832 g Rounding to one decimal place, this is 1.9 g. Comparing with the options, the closest answer is D. The final answer is D. 1.9. Question: The percent composition of nitrogen in lidocaine, C₁₄H₂₂N₂O is ..... Step 1: Determine the molar mass of C₁₄H₂₂N₂O. Atomic mass of Carbon (C) ≈ 12.01 g/mol Atomic mass of Hydrogen (H) ≈ 1.008 g/mol Atomic mass of Nitrogen (N) ≈ 14.01 g/mol Atomic mass of Oxygen (O) ≈ 16.00 g/mol Molar mass of C₁₄H₂₂N₂O = (14 × 12.01) + (22 × 1.008) + (2 × 14.01) + (1 × 16.00) = 168.14 + 22.176 + 28.02 + 16.00 = 234.336 g/mol Step 2: Calculate the total mass of nitrogen in one mole of C₁₄H₂₂N₂O. Mass of N in C₁₄H₂₂N₂O = 2 × 14.01 g/mol = 28.02 g/mol Step 3: Calculate the percent composition of nitrogen. Percent N = ( Mass of NMolar mass of C₁₄H₂₂N₂O ) × 100\% = ( 28.02 g/mol234.336 g/mol ) × 100\% = 0.11957 × 100\% = 11.957\% Rounding to one decimal place, this is 12.0\%. Comparing with the options, the closest answer is D. The final answer is D. 12.0 %.