An alkanol has the following composition by mass: hydrogen 13.5%, oxygen 21.6% and carbon 64.9%. Determine…

Question

An alkanol has the following composition by mass: hydrogen 13.5%, oxygen 21.6% and carbon 64.9%. Determine the empirical formula of the alkanol. (C = 12.0, H = 1.0, O = 16) (2 marks)

ScanSolve AI Tutor · Accepted Answer

Ili kubainisha fomula ya empiriki, tutafuata hatua hizi:

Badilisha asilimia kuwa gramu kwa kudhani tuna sampuli ya 100 g.
- Carbon (C): $64.9 \text{ g}$
- Hydrogen (H): $13.5 \text{ g}$
- Oxygen (O): $21.6 \text{ g}$
Badilisha gramu kuwa mol kwa kutumia masi za atomiki zilizopewa (C = 12.0, H = 1.0, O = 16.0).
- Moli za C:
$\frac{64.9 \text{ g}}{12.0 \text{ g/mol}} = 5.408 \text{ mol}$
- Moli za H:
$\frac{13.5 \text{ g}}{1.0 \text{ g/mol}} = 13.5 \text{ mol}$
- Moli za O:
$\frac{21.6 \text{ g}}{16.0 \text{ g/mol}} = 1.35 \text{ mol}$
Gawanya idadi ya moli kwa idadi ndogo zaidi ya moli ili kupata uwiano rahisi.
Idadi ndogo zaidi ya moli ni $1.35 \text{ mol}$ (ya Oksijeni).
- Uwiano wa C:
$\frac{5.408}{1.35} \approx 4$
- Uwiano wa H:
$\frac{13.5}{1.35} = 10$
- Uwiano wa O:
$\frac{1.35}{1.35} = 1$
Uwiano wa moli ni namba kamili, kwa hivyo fomula ya empiriki ni $C_4H_{10}O$ .
Fomula ya empiriki ya alkanol ni: $C_4H_{10}O$

An alkanol has the following composition by mass: hydrogen 13.5%, oxygen 21.6% and carbon 64.9%. Determine the empirical formula of the alkanol. (C = 12.0, H = 1.0, O = 16) (2 marks)

Answer

Step-by-step solution

Badilisha asilimia kuwa gramu kwa kudhani tuna sampuli ya 100 g.

Badilisha gramu kuwa mol kwa kutumia masi za atomiki zilizopewa (C = 12.0, H = 1.0, O = 16.0).

Gawanya idadi ya moli kwa idadi ndogo zaidi ya moli ili kupata uwiano rahisi.

Uwiano wa moli ni namba kamili, kwa hivyo fomula ya empiriki ni $C_4H_{10}O$ .

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An alkanol has the following composition by mass: hydrogen 13.5%, oxygen 21.6% and carbon 64.9%. Determine the empirical formula of the alkanol. (C = 12.0, H = 1.0, O = 16) (2 marks)

Answer

Step-by-step solution

Badilisha asilimia kuwa gramu kwa kudhani tuna sampuli ya 100 g.

Badilisha gramu kuwa mol kwa kutumia masi za atomiki zilizopewa (C = 12.0, H = 1.0, O = 16.0).

Gawanya idadi ya moli kwa idadi ndogo zaidi ya moli ili kupata uwiano rahisi.

Uwiano wa moli ni namba kamili, kwa hivyo fomula ya empiriki ni C4H10OC_4H_{10}OC4​H10​O.

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Uwiano wa moli ni namba kamili, kwa hivyo fomula ya empiriki ni $C_4H_{10}O$ .