How many moles of Fe2O3 are contained in 1kg of the compound? Fe=56,O=16
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Calculate the molar mass of $\text{Fe}_2\text{O}_3$.
The atomic mass of Fe is 56 g/mol.
The atomic mass of O is 16 g/mol.
$$ \text{Molar mass of } \text{Fe}_2\text{O}_3 = (2 \times \text{atomic mass of Fe}) + (3 \times \text{atomic mass of O}) $$
$$ \text{Molar mass of } \text{Fe}_2\text{O}_3 = (2 \times 56 \text{ g/mol}) + (3 \times 16 \text{ g/mol}) $$
$$ \text{Molar mass of } \text{Fe}_2\text{O}_3 = 112 \text{ g/mol} + 48 \text{ g/mol} $$
$$ \text{Molar mass of } \text{Fe}_2\text{O}_3 = 160 \text{ g/mol} $$
Step 2: Convert the given mass from kilograms to grams.
$$ \text{Mass} = 1 \text{ kg} \times \frac{1000 \text{ g}}{1 \text{ kg}} = 1000 \text{ g} $$
Step 3: Calculate the number of moles.
$$ \text{Moles} = \frac{\text{Mass}}{\text{Molar mass}} $$
$$ \text{Moles of } \text{Fe}_2\text{O}_3 = \frac{1000 \text{ g}}{160 \text{ g/mol}} $$
$$ \text{Moles of } \text{Fe}_2\text{O}_3 = 6.25 \text{ mol} $$
The number of moles of $\text{Fe}_2\text{O}_3$ in 1 kg of the compound is $\boxed{\text{6.25 mol}}$.
