This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Hey king, good to see you again. Here's the solution for 5(a)(i): Step 1: Calculate the molar mass of ammonium chloride (NH_4Cl). The atomic masses are given as N = 14.0, H = 1.0, Cl = 35.5. Molar mass of NH_4Cl = (1 × 14.0) + (4 × 1.0) + (1 × 35.5) Molar mass of NH_4Cl = 14.0 + 4.0 + 35.5 = 53.5 g mol^-1 Step 2: Convert the volume of the solution from cm^3 to dm^3. Given volume = 200 cm^3. Since 1 dm^3 = 1000 cm^3: Volume = (200)/(1000) dm^3 = 0.2 dm^3 Step 3: Calculate the number of moles of ammonium chloride. The concentration is 0.5 mol dm^-3 and the volume is 0.2 dm^3. Moles = Concentration × Volume Moles = 0.5 mol dm^-3 × 0.2 dm^3 = 0.1 mol Step 4: Calculate the mass of ammonium chloride crystals needed. Mass = Moles × Molar mass Mass = 0.1 mol × 53.5 g mol^-1 = 5.35 g The mass of ammonium chloride crystals needed is 5.35 g. Send me the next one 📸