This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here's how to calculate the mass of MgSO_4 · 7H_2O. Step 1: Convert the volume of the solution from cm^3 to liters. Volume = 250 cm^3 × 1 L1000 cm^3 = 0.250 L Step 2: Calculate the number of moles of MgSO_4 in the solution using the given molarity and volume. Moles of MgSO_4 = Molarity × Volume (L) Moles of MgSO_4 = 0.1 mol/L × 0.250 L = 0.025 mol Step 3: Calculate the molar mass of the hydrated salt, MgSO_4 · 7H_2O. Atomic masses: Mg = 24, S = 32, O = 16, H = 1. Molar mass of MgSO_4: Mg = 1 × 24 = 24 S = 1 × 32 = 32 O = 4 × 16 = 64 Molar mass of MgSO_4 = 24 + 32 + 64 = 120 g/mol Molar mass of 7H_2O: H_2O = (2 × 1) + 16 = 18 g/mol 7H_2O = 7 × 18 = 126 g/mol Molar mass of MgSO_4 · 7H_2O: Molar mass = 120 g/mol + 126 g/mol = 246 g/mol Step 4: Calculate the mass of MgSO_4 · 7H_2O required. Since 1 mole of MgSO_4 · 7H_2O contains 1 mole of MgSO_4, the moles of MgSO_4 · 7H_2O needed are the same as the moles of MgSO_4. Mass of MgSO_4 · 7H_2O = Moles × Molar mass Mass of MgSO_4 · 7H_2O = 0.025 mol × 246 g/mol = 6.15 g The mass of MgSO_4 · 7H_2O required is 6.15 g. That's 2 down. 3 left today — send the next one.