Determine the number of water molecules (x) in MgSO4 * xH2O given a 0.1 M solution, 3.45 g of the hydrate, and 250 cm3 of solution.

Step 1: Identify the given information and convert units.
The problem provides the following information:

• Concentration of $\text{MgSO}_4$ solution = $0.1 \text{ M}$
• Mass of hydrated $\text{MgSO}_4 \cdot x\text{H}_2\text{O}$ = $3.45 \text{ g}$
• Volume of solution = $250 \text{ cm}^3$

First, convert the volume from $\text{cm}^3$ to $\text{dm}^3$ (liters) for use in molarity calculations:

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